Is there an image that goes with this question?
Answer:
f = v / 4L
the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.
Explanation:
In wind instruments the wave speed must meet
v = λ f
λ = v / f
from v is the speed of sound that depends on the temperature
v = v₀
where I saw the speed of sound at 0ºC v₀ = 331 m/s the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation
(F -32) 5/9 = C
76ºF = 24.4ºC
45ºF = 7.2ºC
With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside
at T₁ = 24ºC v₁ = 342.9 m / s
at T₂ = 7ºC v₂ = 339.7 m / s
To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change
λ / 4 = L
λ= 4L
v / f = 4L
f = v / 4L
Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.
They hit each other.This is the 3rd law I think
Answer:
Vy = -Vx * cotg(θ)
Explanation:
From the Pythagoras theorem:
X^2 + Y^2 = L^2
The first derivative respect of time is:
2*X*Vx + 2*Y*Vy = 0
X*Vx = -Y*Vy
Vy = -Vx * X/Y
From trigonometry:
X = L * cos(θ)
Y = L * sin(θ)
X/Y = (L *cos(θ)) / (L * sin(θ))
X/Y = cotg(θ)
Vy = -Vx * cotg(θ)
The speed does not depend on the length of the arm L.
Answer:
A moving electric charge behaves like a mini-magnet as it creates its own magnetic field. This means it experiences a force if it moves through an external magnetic field (in the same way that a mass experiences a force in a gravitational field or a charge experiences a force in an electric field.)