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2 years ago

I'm really lost on this problem

Mathematics

1 answer:

Alenkinab [10]2 years ago

5 0

Since you need a little bit of trigonometry to solve this problem,
I'm pretty sure you've had a little bit of trigonometry in class before
you were assigned to solve this problem.

-- The shaded triangle comes from taking the equilateral triangle and
either folding it in half or cutting it in half.

-- The base that the new triangle is standing on is 1/2 the base of the
equilateral triangle, so it's 7 cm long.

-- The acute angle at the right end of the base is the same as it was in
the equilateral triangle . . . 60 degrees.

-- The tangent of 60 degrees is (opposite side)/(adjacent side) = x / 7 cm

tan(60) = x/7

-- Multiply each side of this little equation by 7 : 7 tan(60) = x

If you don't have the tangent of 60 degrees in your pocket, you can
find it with your calculator. Multiply it by 7, and Shazam, you know 'x' .

You might be interested in

Need help finding the area of the shaded region. Round to the nearest tenth. Need help ASAP

Sergio [31]

Answer: 294.4 m²

Step-by-step explanation:

Separate the shaded region into two parts:

The section containing the central angle of 230° (360° - 130°)
The triangle with sides 11.1, 11.1 & 20.12 (use Law of Cosines)

$1.\ Area(A)=\pi\ r^2\ \bigg(\dfrac{\theta}{360}\bigg)\\\\\\.\qquad \qquad =\pi(11.1)^2\bigg(\dfrac{230}{360}\bigg)\\\\\\.\qquad \qquad =247.3$

$2.\ \text{Use Law of cosines to find the length of the third side.}\\\text{ Then use Heron's formula to find the Area of the triangle.}\\\\s=\dfrac{11.1+11.1+20.12}{2}=21.16\\\\\\A=\sqrt{s(s-a)(s-b)(s-c)}\\\\.\ =\sqrt{21.16(21.16-11.1)(21.16-11.1)(21.16-20.12)}\\\\.\ =\sqrt{2227}\\\\.\ =47.1$

Area of shaded region = Area of (1) + Area of (2)

= 247.3 + 47.1

= 294.4

8 0

3 years ago

Read 2 more answers

3(x-1) - 8 = 4(1+x) +5. Too hard, i keep getting confused

svet-max [94.6K]

3(x-1)-8=4(1+x)+5

One solution was found :

x = -20

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

3*(x-1)-8-(4*(1+x)+5)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((3•(x-1))-8)-(4•(x+1)+5) = 0

Step 2 :

Equation at the end of step 2 :

(3 • (x - 1) - 8) - (4x + 9) = 0

Step 3 :

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

-x - 20 = -1 • (x + 20)

Equation at the end of step 4 :

-x - 20 = 0

Step 5 :

Solving a Single Variable Equation :

5.1 Solve : -x-20 = 0

Add 20 to both sides of the equation :

-x = 20

Multiply both sides of the equation by (-1) : x = -20

One solution was found :

x = -20

hope this is wht u wanted

4 0

3 years ago

Contains the x intercept of 4x-y=8 and the point (-4,3)

nydimaria [60]

1. 4x –y = 8, the point (-4, 3)
Let’s say y = 0
=> 4x – 8
=> 4x / 4 = 8 /4
=> x = 2
So the point is (2 , 0).
Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=> m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1

7 0

3 years ago

Read 2 more answers

C=wtc/1000 solve for w

Nutka1998 [239]

For this case we have the following equation:
$C = \frac{wtc}{1000}$
To clear w, we must follow the following steps:
1) The value of t multiplied by c pass to divide the other side of the equation:
$\frac{w}{1000} = \frac{C}{tc}$
2) the value of 1000 is passed to multiply to the other side of the equation:
$w = \frac{1000C}{tc}$
Answer:
The cleared equation for w is:
$w = \frac{1000C}{tc}$

3 0

3 years ago

Read 2 more answers

Isolate the h in c=25h+350

Sati [7]

Subtract 350 from both sides then divide both sides by 25.

(c-350)/25 = h

7 0

2 years ago