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3 years ago

Products of a neutralization reaction

Chemistry

1 answer:

Lemur [1.5K]3 years ago

7 0

Neutralization is the reaction of an acid and a base which form water and a salt

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Please help with #2 and #3

Vaselesa [24]

Answer:

2. $V_2=17L$

3. $V=82.9L$

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

$\frac{V_2}{T_2}=\frac{V_1}{T_1}$

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

$V_2=\frac{V_1T_2}{T_1}$

Therefore, we plug in the given data to obtain:

$V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L$

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

$V=\frac{nRT}{P}$

Therefore, we plug in the data to obtain:

$V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L$

Best regards!

6 0

3 years ago

Give four method of acid preparation and give two reactions to support your answers

gregori [183]

(i) Hydrogen chloride gas is prepared by treating Sodium chloride with concentrated sulphuric acid. The HCl gas is passed through a drying agent to remove moisture where concentrated sulphuric acid plays the role of dehydrating agent as well.

(ii) NaCl+H2 SO4 →NaHSO 4 +HCl(g)

Hope it helps :)

5 0

3 years ago

Read 2 more answers

Calculate the volume of chlorine at stp that would be required to act completely with 3.70g of dry slaked line

myrzilka [38]

Answer:

The volume required is 2.24L

Explanation:

The slaked lime Ca(OH)2, reacts with chlorine, Cl2, as follows:

6Cl₂(g) + 3Ca(OH)₂(s) → Ca(ClO₃)₂ (aq) + 2CaCl₂ (aq) + 6HCl (aq)

Where 6 moles of chlorine react with 3 moles of slaked llime,

To solve this question we must find the moles of slaked lime added. With these moles we can find the moles of chlorine required and its volume at STP as follows:

Moles Ca(OH)2 - Molar mass: 74.093g/mol-

3.70g * (1mol / 74.093g) = 0.0500 moles Ca(OH)2

Moles Cl₂:

0.0500 moles Ca(OH)2 * (6 mol Cl₂ / 3 mol Ca(OH)2) =

0.100 moles Cl₂

Now using PV = nRT

nRT / P = V

Where n are moles: 0.100 moles

R is gas constant = 0.082atmL/molK

T is absolute temperature = 273K at STP

P is pressure = 1atm at STP

And V is volume, our incognite:

0.100mol*0.082atmL/molK*273K / 1atm = V

2.24L = Volume of Cl₂

<h3>The volume required is 2.24L</h3>

8 0

3 years ago

Please answer this question for me!

PolarNik [594]

Answer:

i can send u all of the bio stuff i have maybe it will help

Explanation:

4 0

3 years ago

1. 1.204 x 1024 atoms He = ? moles He

Fantom [35]

Check your chemistry textbook (or class notes) concerning molar mass, then look up the value for oxygen.

Then divide Avogadro’s number into the given amount of atoms, to find the number of moles.

Then combine this result appropriately with the molar mass, and voilà!

…Then reconsider posting homework questions without showing the work you have already done.

5 0

3 years ago