10H₂ + 5O₂ → 10H₂O
Explanation:
This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:
"In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".
This meaning of this is that; the number of atoms on each side of the expression must be the same.
2H₂ + O₂ → 2H₂O
let us check is the equation above is balanced;
2H₂ + O₂ → 2H₂O
Elements reactant product
H 4 4
O 2 2
We can see vividly that the equation is balanced;
Now; if we have 5 oxygen gas, we multiply the equation through by 5:
5 x ( 2H₂ + O₂ → 2H₂O )
⇒ 10H₂ + 5O₂ → 10H₂O
Elements reactant product
H 20 20
O 10 10
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Balanced equation brainly.com/question/11102790
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Answer:
6.32 × 10⁻³
3.2560008× 10⁷
5.630× 10⁰
9.5002× 10¹
Explanation:
Scientific notation is the way to express the large value in short form.
The number in scientific notation have two parts.
The digits (decimal point will place after first digit)
× 10 ( the power which put the decimal point where it should be)
For example:
0.00632
In scientific notation = 6.32 × 10⁻³
32,560,008
In scientific notation = 3.2560008× 10⁷
5.630
In scientific notation = 5.630× 10⁰
95.002
In scientific notation = 9.5002× 10¹
Answer:
20 atoms
Explanation:
There are 4 in H2O2 because of 2 hydrogens and 2 oxygens.
Then, multiply by 5 because the coefficient is 5, therefore there are 5 H2O2 molecules.
5 x 4 = 20
Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.
Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x
By proportion,
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
17.586x+117.24 = 240
x=122.78/17.586
=6.980
Answer: there are 7 water of hydration in Epsom salt, according to the experiment.
Note: more accurate (proper) results may be obtained by using exact values (3-4 significant figures) in the molecular masses. However, since water of hydration is the nearest integer, using approximate values (to at least two significant figures) suffice.
