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Dima020 [189]
2 years ago
15

Determine how many mm of Hg are equal to 5.3 atm of pressure

Chemistry
1 answer:
Leno4ka [110]2 years ago
5 0
4028 mm of Hg...........
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Isopropyl alcohol is mixed with water to produce a 35.0 % (v/v) alcohol solution. How many milliliters of each component are pre
PilotLPTM [1.2K]

229.25 mL of isopropyl alcohol

425.75 mL of water

Explanation:

Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.

volume of  isopropyl alcohol = (35/100) × solution volume

volume of  isopropyl alcohol = 0.35 × 655 mL = 229.25 mL

Now, knowing the volume of isopropyl alcohol we can determine the volume of water.

volume of the solution = volume of isopropyl alcohol + volume of water

volume of water = volume of the solution - volume of isopropyl alcohol

volume of water = 655 mL - 229.25 mL = 425.75 mL

Learn more about:

percent by volume concentration

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2 years ago
What is the name of the element that has electrons arranged <br>2,8,2 ​
poizon [28]

Answer:

The metal element → Magnesium (Mg)

7 0
3 years ago
Read 2 more answers
. How many grams of water would require 4400 joules
Alja [10]

Answer:

The specific heat of water is 4.18 J/g C.

Explanation:

q

=

m

C

s

Δ

T

Never forget that!

2200

=

m

⋅

4.18

J

g

⋅

°

C

⋅

66

°

C

∴

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≈

8.0

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5 0
2 years ago
a gas has a volume of 350 cubic centimeters at 740 mmHg. how many cubic centimeters will the gas occupy at a pressure of 900 mmH
Harrizon [31]

Answer: 287.8 cm3

Explanation:

Given that:

Initial volume of gas V1 = 350 cm3

Initial pressure of gas P1 = 740 mmHg

New volume V2 = ?

New pressure P2 = 900 mmHg

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

740 mmHg x 350 cm3 = 900mmHg x V2

V2 = (740 mmHg x 350 cm3) /900mmHg

V2 = 259000 mmHg cm3 / 900mmHg

V2 = 287.8 cm3

Thus, the gas will occupy 287.8 cubic centimeters at the new pressure.

3 0
2 years ago
Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat
Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

4 0
2 years ago
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