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sp2606 [1]
3 years ago
7

The compound HA is an acid that is soluble in water which of the beakers in the picture shows HA behaving as a weak acid in wate

r?

Chemistry
1 answer:
lesya692 [45]3 years ago
6 0
HA is a weak acid so there should be little amount of HA and then H+ and A- in the beaker so the last one is true a weak acid never converts completely to H+ and A-
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What is the molar mass of C4H2?
fenix001 [56]

Answer:

(12×4)+(1×2)=50

Explanation:

mass of Carbon is 12....mass of hydrogen is 1

6 0
3 years ago
The combustion of carbohydrates and the combustion of fats are both exothermic processes, yet the combustion of carbohydrates is
saveliy_v [14]

Explanation:

Combustion of a compound is the reaction with oxygen , hence , the process of combustion is an oxidation reaction.

The carbohydrates contain more amount of oxygen as compared to the fats ,

Hence ,

carbohydrates , have a lot of oxygen contents , are are already partially oxidized , but fats have lower oxygen content .

Therefore ,

The partially oxidized carbohydrates are very difficult to oxidized in comparison to fats .

4 0
3 years ago
How many grams of neutral salt will be obtained in the reaction of calcium oxide with 200 cm 3 of phosphoric acid solution whose
katen-ka-za [31]

Answer:

9.3 g of Ca3(PO4)2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

Next, we shall determine the number of mole of H3PO4 present in 200 cm³ of 0.3 mol/dm³ phosphoric acid (H3PO4) solution. This can be obtained as follow:

Molarity of H3PO4 = 0.3 mol/dm³

Volume = 200 cm³ = 200 cm³/1000 = 0.2 dm³

Mole of H3PO4 =?

Molarity = mole /Volume

0.3 = mole of H3PO4 /0.2

Cross multiply

Mole of H3PO4 = 0.3 × 0.2

Mole of H3PO4 = 0.06 mole

Next, we shall determine the number of mole of the salt, Ca3(PO4)2, obtained from the reaction. This can be obtained as shown below:

3CaO + 2H3PO4 —> Ca3(PO4)2 + 3H2O

From the balanced equation above,

2 moles of H3PO4 reacted to produced 1 mole of Ca3(PO4)2.

Therefore, 0.06 moles of H3PO4 will react to produce = (0.06 × 1)/2 = 0.03 mole of Ca3(PO4)2.

Thus, 0.03 mole of Ca3(PO4)2 is produced from the reaction.

Finally, we shall determine the mass of Ca3(PO4)2 produced as follow:

Mole of Ca3(PO4)2 = 0.03 mole

Molar mass of Ca3(PO4)2 = (40×3) + 2[31 + (16×4)]

= 120 + 2[31 + 64]

= 120 + 2[95]

= 120 + 190

= 310 g/mol

Mass of Ca3(PO4)2 =?

Mole = mass /Molar mass

0.03 = mass of Ca3(PO4)2 / 310

Cross multiply

Mass of Ca3(PO4)2 = 0.03 × 310

Mass of Ca3(PO4)2 = 9.3 g

Thus, 9.3 g of Ca3(PO4)2 was obtained from the reaction.

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2 years ago
Balancing oxidation-reduction reactions <br> Mg+ N2—&gt;Mg3N2
BartSMP [9]

Answer:

{ \sf{3Mg_{(s)} + N_{2(g)} →Mg _{3}N_{2(s)}}}

3 0
3 years ago
Explain ionization suppressants as applied to atomic spectrometry
levacccp [35]

An ionization suppressor is an alkali metal capable of preventing ionization, which can be used in atomic spectroscopy to determine matter composition.

<h3>What is ionization?</h3>

Ionization refers to the phenomena capable of converting neutral atoms/molecules to electrically charged atoms/ions.

Ionization is a process by which radiation (e.g., alpha, beta, gamma rays) can pass energy to inert matter.

Some examples of ionization suppressors include salts of alkali metals (for example, potassium), which can be used in atomic spectroscopy to determine matter composition.

Learn more about ionization here:

brainly.com/question/1445179

8 0
2 years ago
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