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Alenkasestr [34]
2 years ago
14

Two students are running down the hallway towards each other. Student 1 has a mass of 107kg and is running to the right at 4.1m/

s. Student 2 has a mass of 97kg and is running to the left at 7.1m/s. If they strike in an elastic collision, what is the velocity of student 2 if student 1 moves at 6.55m/s to the left after the collision?
Physics
1 answer:
antiseptic1488 [7]2 years ago
3 0

Answer:

Hi

Explanation:

You are awesome

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Answer:

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I=4(\frac{ma^{2} }{4} )=ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}

b) Distance from top left mass = x = a/2

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The total moment of inertia is:

I=m(\frac{a}{2} )^{2} +m(\frac{a}{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}=\frac{12ma^{2} }{4} =3ma^{2} =3*0.98*(4.14)^{2} =50.39kgm^{2}

c)

I=2m(\frac{m}{\sqrt{2} } )^{2} =ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}

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