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fredd [130]
4 years ago
6

Please ans fast I will mark brainliest For sure

Physics
1 answer:
mixas84 [53]4 years ago
6 0
Well for starters, that means that the air in the sky is very cold, and has a lower temperature. Since it is super dark, it is colder than the polar bear.

The polar bear is cold. Not as cold as the sky, and not as warm as the mouth and eyes, but it is still very cold. This is probably because it lives in a snowy and cold climate.

The polar bears eyes and mouth are warm. This is because, the spots where the eyes, mouth, and nose are is a very light shade. This concludes that those spots on the polar bear are warm.
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The unstretched rope is 20 meters. After getting dunked a few times the 80 kg jumper comes to rest above the water with the rope
Kamila [148]

Answer:

Therefore maximum stretch is y2 = 32.36 m

Explanation:

In this problem let's use the initial data to find the string constant, let's apply Newton's second law when in equilibrium

        F_{e} - W = 0

         k Δx = mg

         k = mg / Δx

         k = 80 9.8 / (30-20)

         k = 78.4 N / m

now let's use conservation of energy to find the velocity of the body just as the string starts to stretch y = 20 m

starting point. When will you jump

         Em₀ = U = mg y

final point. Just when the rope starts to stretch

         Em_{f} = K = ½ m v²

         Em₀ = Em_{f}

          mg y = ½ m v²

          v = √ 2g y

          v = √ (2 9.8 20)

          v = 19.8 m / s

now all kinetic energy is transformed into elastic energy

starting point

            Em₀ = K = ½ m v²

final point

            Em_{f} = K_{e} + U = ½ k y² + m g y

            Emo = Em_{f}

           ½ m v² = ½ k y² + mgy

            k y² + 2 m g y - m v² = 0

         

we substitute the values ​​and solve the quadratic equation

            78.4 y² + 2 80 9.8 y - 80 19.8² = 0

            78.4 y² + 1568 y - 31363.2 = 0

              y² + 20 y - 400 = 0

              y = [- 20 ±√ (20 2 +4 400)] / 2

              y = [-20 ± 44.72] / 2

the solutions are

              y₁ = 12.36 m

              y₂ = 32.36 m

These solutions correspond to the maximum stretch and its rebound.

Therefore maximum stretch is y2 = 32.36 m

7 0
3 years ago
If you pluck a guitar string hard the sound waves it gives off will have __________ amplitudes.
Ilia_Sergeevich [38]

Answer:

large

Explanation:

the harder you pluck the louder it gets

4 0
4 years ago
Read 2 more answers
A police car is traveling at a speed of 50 meters per second when it suddenly accelerates at a rate of 5 m/s2. How fast will the
Virty [35]

Answer:i don't know sorry good luck tho

Explanation: i have not learned it yet

6 0
4 years ago
A sound wave has a wavelength of 0.450 meters. If its speed in cold air is 330 meters/second, what is the wave's frequency?
faust18 [17]
Most of the information's required are already given in the question. Based on those information's the answer can be easily deduced.
Wavelength of the sound wave = 0.450 meters
Speed of the sound wave = 330 meters per second
We already know
v=f<span>λ
</span>330 = f * 0.450
f = 330/0.450
  = 733.33 hertz
So the frequency of the wave is 733.33 hertz
5 0
4 years ago
Read 2 more answers
Which planet has the greatest mass?
Firlakuza [10]

Answer:

Jupiter

Explanation:

The largest planet in our solar system by far is Jupiter, which beats out all the other planets in both mass and volume. Jupiter's mass is more than 300 times that of Earth, and its diameter, at 140,000 km, is about 11 times Earth's diameter.

Note:

Please mark as Brainliest! <3

5 0
3 years ago
Read 2 more answers
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