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Blababa [14]
3 years ago
6

Explain.Car side mirrors do not work when they are convered with frost. What does frost do no the surface of a mirror to cause a

diffuse reflection?
​
Chemistry
1 answer:
lozanna [386]3 years ago
8 0

Answer:

Explanation:

Search it to google.

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7 0
2 years ago
A polonium atom has 84 protons, 124 neutrons, and 84 electrons. What will it change to during alpha decay? A. A lead atom with 8
77julia77 [94]
I think the correct answer would be A. When a polonium atom with 84 protons, 124 neutrons, and 84 electrons undergoes alpha decay, a lead atom would be produced with 82 protons, 122 neutrons, and 84 electrons together with an alpha particle having two protons and two neutrons.
3 0
3 years ago
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The equation shows lead reacting with sulfuric acid to produce lead sulfate and hydrogen gas. mc012-1.jpg Which type of chemical
krok68 [10]
Single replacement and I know that for sure if you need me to explain i can but its Single replacement <span />
4 0
3 years ago
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An order is given to administer 57 g of lactulose syrup, often used for treating complications of liver disease. The suspension
Angelina_Jolie [31]

Answer : The volume given to the patient should be, 85.5 mL

Explanation :

As we are given that the suspension contains 10g/15mL.

Now we have to determine the volume should be given to the patient.

As, 10 grams of lactulose syrup needed 15 mL volume of solution

So, 57 grams of lactulose syrup needed \frac{57g}{10g}\times 15mL=85.5mL volume of solution

Thus, the volume given to the patient should be, 85.5 mL

8 0
2 years ago
1. What is the specific heat (C) of an unknown sample that weighs 5.0 grams, absorbds 250.0j of heat and has a temperature
maks197457 [2]
Note: The question is incomplete. The complete question is given below :
Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)
Explanation:
1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT
Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C
H = 50 × 0.75 × 3 = 112.5 calories
b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g
H = 50 × 45 = 2250 cal
c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.
Amount of energy left = 5000 - 2362.5 = 2637.5 cal
The remaining energy is used to heat the liquid
H = mcΔT
Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change
2637.5 = 50 × 0.75 x ΔT
ΔT = 2637.5 / ( 50*0.75)
ΔT = 70.3 °C
Final temperature of sample = (70.3 + 27) °C = 97.3 °C
The substance will be in liquid state at a temperature of 97.3 °C

i hope that this eg gonna help u
7 0
2 years ago
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