How will adding NaCl affect the freezing point of a solution?

1 answer:

7 0

Answer is: adding NaCl will lower the freezing point of a solution. A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water). The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.

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Convert 12 meters per second into miles per hour.

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The balanced net ionic equation for the neutralization reaction involving equal molar amounts of hno3 and koh is ________.

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The net ionic equation for the neutralization reaction involving equal molar amount amount of HNo3 and KoH is

H^+ + OH^- = H2O (l)

explanation
write the chemical equation
HNO3 (aq) + KOH(aq) = KNO3(aq) +H2O (l)

ionic eequation

H^+(aq) + NO3^- (aq) + K^+9aq) OH^-(aq) = K^+ (aq) + NO3^-(aq) + H2O(l)

cancel the spectator ions( ions which does not take place in equation ) for this case is NO3^- and No3^-

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Which of the following represents a propagation step in the monochlorination of methylene chloride (CH2Cl2)?a. CHCl3 + Cl. Right

svetlana [45]

Answer:

B = CHCl2 + Cl2 --> CHCl3 + Cl

Explanation:

Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.

Free radical chlorination is divided into 3 steps which are:

The initiation step

The propagation step

The termination step

So in reference to the question, propagation step involves two steps.

The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.

The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.

You would find in the attachment the 2 step mechanism.

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