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Gnoma [55]
3 years ago
9

When a person looks at a bright light, tiny muscles in the eye contract so less light can enter the eye.

Chemistry
2 answers:
Wewaii [24]3 years ago
7 0

Answer:

nonstriated

involuntary

attached to the eyeball

Explanation:

galben [10]3 years ago
4 0

Answer:

nonstriated, involuntary and attached to eyeball.

Explanation:

You might be interested in
Which machine is the least simple? a bike a screw an inclined plane a lever
Ivenika [448]

Answer: A bike

A bike is composed of various simple machines. It has a wheel and axle as one component, and it also has screws to hold the various parts together, along with levers and pulleys that are connected to the pedals. So all of these simple machine concepts work together to help transport the rider from point A to point B.

The other answer choices of screw, inclined plane, and lever, are fairly simple machines that don't have many things going on at once compared to a bike.

4 0
3 years ago
This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl
nlexa [21]

Answer:

Molality = <u>10.300 m</u>

<u>Molarity = 6.5970 M</u>

<u>mole fraction = </u>0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>

<u />

<u>2) Molarity</u> = number of moles / volume of solution

Since we know the density  of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL   = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>

3) Mole fraction

moles water = 61g / 18.02g/mole  = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0
2 years ago
What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a
Vadim26 [7]

Answer:

\boxed {\boxed {\sf 333 \ grams}}

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

Q= mc \Delta T

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

  • ΔT= final temperature - initial temperature

The sample was heated <em>from </em> 58.8 degrees Celsius to 88.9 degrees Celsius.

  • ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

  • Q= 4500.0 J
  • c= 0.4494 J/g°C
  • ΔT = 30.1 °C

Substitute these values into the formula.

4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)

Multiply on the right side of the equation. The units of degrees Celsius cancel.

4500.0 \ J = m (13.52694 J/g)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}

The units of Joules cancel.

\frac {4500.0 \ J }{13.52694 J/g}= m

332.6694729 \ g =m

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

333 \ g \approx m

The mass of the sample of metal is approximately <u>333 grams.</u>

8 0
2 years ago
H2CO3(aq) → CO2(aq) + H2O(l) After strenuous exercise, you breathe heavily, exhaling and removing CO2 from your body. The remova
Aleksandr-060686 [28]

Answer:

did you find the answer

Explanation:

help

6 0
2 years ago
Water that has condensed and formed water droplets on the ground, grass, and other outdoor objects is known as _____.
Amanda [17]
The correct answer is B. Water that has condensed and formed water droplets on the ground, grass, and other outdoor objects is known as dew. It is water formed due to condensation in early morning or evening. It is formed when the temperature of the objects reach below the dew point of the air around.
5 0
3 years ago
Read 2 more answers
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