This is a division problem. First, get 12 1/3 into fraction form instead of mixed number form to make your life easier;
Now, divide the two fractions. Since this is fraction division, the reciprocal is flipped and the two fractions multiplied.
The answer from the fraction division is 16 and four-ninths, but because you need a whole number as an answer,
the answer is 16 pieces.
The answer for that equation will be 0.375.
Step-by-step explanation:
x + 6 = 2x - 8
1. Subtract 2x from both sides
x - 2x + 6 = 2x - 2x - 8
2. Simplify
-x + 6 = -8
3. Now, subtract 6 from both sides
-x + 6 - 6 = -8 - 6
4. Simplify
-x = -14
5. Divide both sides by -1 because you would want the x by itself instead of having -x
-1x/-1 = -14/-1
6. Simplify
x = 14 <------ Answer
Hope that helped!!
~Shane
Answer:

this is the equation of the tangent at point (-1,1/e)
Step-by-step explanation:
to find the tangent line we need to find the derivative of the function g(x).

- we know that



this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'
to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

using the equation of line:

we'll find the equation of the tangent line.
here (x1,y1) =(-1,1/e), and m = 3/e


this is the equation of the tangent at point (-1,1/e)
Answer:
B
Step-by-step explanation:
plz give brainliest i have never got it