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11111nata11111 [884]
3 years ago
15

The Synthesis Reaction of aluminum (Al) and iodine (I) forms a new, more complex

Chemistry
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

Aluminum iodide (AlI₃)

Explanation:

The synthesis reaction of aluminum (Al) and iodine (I) can be illustrated as shown below:

Aluminium exhibit trivalent positive ion (Al³⁺)

Iodine exhibit univalent negative ion (I¯)

During reaction, there will be an exchange of ion as shown below:

Al³⁺ + I¯ —> AlI₃

Thus, we can write the balanced equation for the reaction as follow:

Al + I₂ —› AlI₃

There are 2 atoms of I on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of AlI₃ and 3 in front of I₂ as shown below:

Al + 3I₂ —› 2AlI₃

There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:

2Al + 3I₂ —› 2AlI₃

Thus the equation is balanced.

The product on the reaction is aluminum iodide (AlI₃)

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How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL
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Explanation:

We are given;

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  • Molarity of HCl as 1.75 M

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That is;

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Second, we determine the number of moles of HCl

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                             = 1.75 M × 3 L

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Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

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The overview of the subject is outlined underneath in the summary tab.

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