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3 years ago

Which wind blows cool air toward the sea at night ?

Chemistry

2 answers:

alexira [117]3 years ago

6 0

Answer:

Land breeze is the wind that blows cool air from land towards sea at night.

Explanation:

Land breeze is a type of wind which is cool and blows towards sea. It occurs due to the difference in the temperature of water and land. At night, the lands cool quickly due to the removal of heat from it. So the air that is present on land is cool down and this air moves towards sea. So this breez is called land breeze because it moves from land.

vfiekz [6]3 years ago

4 0

Answer:

Its sea breeze

Explanation:

land breeze happens in the day time, also i just got it right.

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Vitek1552 [10]

Answer:

The water in the hydrate (referred to as "water of hydration") can be removed by heating the hydrate. When all hydrating water is removed, the material is said to be anhydrous and is referred to as an anhydrate.

Explanation:

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2 years ago

Inorganic compounds which are found in the earth are called

saul85 [17]

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2 years ago

How many 5 MB mp3 files can be stored on a 1 GB flash drive?

tester [92]

Answer:

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Explanation:

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2 years ago

I NEED HELP PLEASE, THANKS! :)

krok68 [10]

Answer:

$\large \boxed{\text{2.20 g Pb}}$

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 239.27 32.00 207.2

2PbS + 3O₂ ⟶ 2Pb + 2SO₃

m/g: 2.54 1.88

2. Calculate the moles of each reactant

$\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}$

3. Calculate the moles of Pb from each reactant

$\textbf{From PbS:}\\\text{Moles of Pb} = \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}$

4. Calculate the mass of Pb

$\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}$

5 0

2 years ago

274 l is equal to: 2.74 ml 27.4 ml 274 ml 2,740 ml

devlian [24]

1 L ---------- 1000 mL
274 L ------- ??

274 x 1000 / 1 => 2,740 mL

hope this helps!

8 0

3 years ago