1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mrs_skeptik [129]
3 years ago
14

Which elements have the most similar chemical properties

Chemistry
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

Elements that belong to the <em>same </em><em>GROUP</em><em> </em>of the periodic table have the most similar chemical properties.

Explanation:

A GROUP in the periodic table is a column of elements with the same number of valence electrons. Since electrons are exchanged/shared during a chemical reaction, then elements with similar valence electrons, will react similarly. Thus elements belonging to the <em>same GROUP</em> are most similar in the way they react.

For example: Sodium and Lithium are group 1 elements while fluorine and chlorine are group 17 elements. In a reaction under normal conditions, Sodium and Lithium will both try to give up their single valence electron to form cations. In doing so they will react more similarly. On the other hand, Fluorine and Chlorine who are more inclined to accept a single electron to form cations react less like the group 1 elements and more like each other.

You might be interested in
What happens when: sulphuric acid reacts with zinc.​
KonstantinChe [14]

Answer:

hope it helps.

Explanation:

Zinc metal dissolves slowly in dilute sulphuric acid to form solutions containing the aquated Zn(II) ion together with hydrogen gas, H2.

3 0
3 years ago
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride. A reaction mixture at 298.15k initially c
uranmaximum [27]

Step 1 : Write balanced chemical equation

The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

I_{2}  (g) + Cl_{2}  (g) ----->  2 ICl (g)

Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

K_{eq} = \frac{[ICl]^{2}}{[I_{2}][Cl_{2}]}

Step 4 : Solving for x

Keq at 298.15 K is given as 81.9

Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table

81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]

4x^{2} = 81.9x^{2} -57.8x +9.66

77.9x^{2} -57.8x+9.66 = 0

Solving the above equation using quadratic formula we get

x = 0.488 or x = 0.254

The value 0.488 cannot be used because the change (C) cannot be greater that initial concentration of the reactants.

Therefore the change in concentration of the gases during the reaction is 0.254 M

Hence, x = 0.254 M

From the ICE table, we know that the equilibrium concentration of ICl is 2x

[ICl]_{eq} = 2 ( 0.254) = 0.508 M

The concentration of ICl when the reaction reaches equilibrium is 0.508 M

6 0
3 years ago
NEEED HELP PLEASE IM VERY STRESSED
Arte-miy333 [17]

Answer:

C) It moves faster and collects more data

Explanation:

5 0
3 years ago
Which property does a metal with a large number of free-flowing electrons most likely have?
Akimi4 [234]

a metal with a large number of free-flowing electrons most likely have good conductivity

6 0
3 years ago
Read 2 more answers
Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^---------&gt;Zn E°cell = -0.76 V Cu^2+ + 2 e^-----
Neko [114]

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

5 0
3 years ago
Other questions:
  • Compound X has the same molecular formula as butane but has a different boiling point and melting point. What can be concluded a
    6·1 answer
  • 4. If an experimental value for a given observation was 415 nm while the theoretical value
    14·1 answer
  • When backpacking in the wilderness, hikers often boil water to sterilize it for drinking. Suppose that you are planning a backpa
    6·1 answer
  • What is the density of a 5 gram sample that occupies a volume of 10 ml
    8·1 answer
  • Hi there needing help with the IUPAC names for these compounds
    12·1 answer
  • 1.00 mL of a 250.0 µM solution of KCl is diluted to 50.0 mL. What is concentration of this solution?
    12·1 answer
  • Which of the following is an example of a Lewis base?
    10·1 answer
  • How many moles are in 43 grams of lithium (LI)?
    6·1 answer
  • If you look at the reflection of your face on the back of a spoon, your face will be right-side up. If you flip the spoon to the
    14·2 answers
  • Briefly describe how the Sun produces energy
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!