Answer:
Copper(II) sulphate – sodium hydroxide reaction
The reaction between copper(Il) sulphate and sodium hydroxide solutions is a good place to start. If you slowly add one to the other while stirring, you will get a precipitate of copper(II) hydroxide, Cu(OH)2.
H3PO4 has molecular weight of approximately 98 grams per
mole. 4.50 M is equal to 4.50 mole per 1000 mL solution of H3PO4. 255 mL times
4.50 mol /1000 mL times 98 g/mol is equal to 112.455 grams. Note that I
automatically equate 1 Liter to 1000 mL since the given volume is in mL for
easier computation.
Substances that cannot be separated and found on a periodic table are elements.
Answer:
moles
Explanation:
The reaction equation is given as:
4NH₃ + 5O₂ → 4NO + 6H₂O
The number of moles of O₂ that completely reacted is given as 1 mole
To solve this problem, we are going to use a stoichiometric approach from the balanced reaction equation:
5 moles of O₂ will react completely to produce 4 moles of NO
1 mole of O₂ will therefore react to produce x mole of NO
5x = 4
x = moles of NO
Magnesium will give two electrons to oxygen and both will become ions.
