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12345 [234]
2 years ago
6

Find the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x2, y =

4x; about the y-axis v = incorrect: your answer is incorrect.
Physics
1 answer:
Simora [160]2 years ago
4 0

The correct answer for  the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x2, y = 4x is 128/3 * π.

Volume of Solid of Revolution by Shell method is given by

V = 2π * integrate x(height) dx Here, height = 4x-x2

(1)& x-varies from x = 0 to x = 4 then from eqn(1)  V = 2π * integrate x(4x - x ^ 2) dx from x = 0 to 4 = 2π * integrate (4x ^ 2 - x ^ 3) dx from x = 0 to 4

Basic Rule(1) ∫ x^n dx =x^ n+1/ n+1

V=2 π [4((x ^ 3)/3) - (x ^ 4)/4] 0 ^ 4 =2 π[ 4/3 x^ 3 - x^ 4/4 ] 0 ^ 4

V = 2π [4/3 * 4 ^ 3 - (4 ^ 4)/4} - 0]

V = 128/3 * π.

Learn more about area under curve here :-

brainly.com/question/15122151

#SPJ4

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What is the speed of a wave with 3Hz frequency and a wavelength of 9 m
SIZIF [17.4K]

Answer:

Given

Frequency (f) = 3Hz

Wavelength = 9 m

Speed = ?

Explanation:

we know

Speed = wavelength * frequency

= 9*3

= 27 m/ s

7 0
3 years ago
A force of 40N is applied to a 28 g mass, what is the acceleration? (round to the hundredths place)
Leno4ka [110]

Answer:

1428.6m/s²

Explanation:

Given parameters:

Force applied on the body  = 40N

Mass of the body  = 28g

                    1000g  = 1kg

                      28g will therefore be 0.028kg

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use the expression derived from Newton's second law of motion.

         Force  = mass x acceleration

Insert the parameters and solve;

            40  = 0.028 x acceleration

           Acceleration  = \frac{40}{0.028}   = 1428.6m/s²

7 0
3 years ago
At 2 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i
labwork [276]

Answer:

The distance between the ships changing at 6PM is 21.29Km/h

Explanation:

Ship A is sailing east at 35Km/h and ship B is sailing West at 25Km/h

Given

dx/dt= 35

dy/dt= 25

dv/dt= ???? at t= 6PM - 2PM= 4

Therefore t=4

We know ship A travels at 150km in the x-direction and Ship A at t=4 travels at 4.35 Which is 140 also in x-direction

So, we use:

D^2 = (150 - x)^2 + y^2;

D^2 = (150 - 140)^2 + y^2

But ship B travels at t=4, at 4.25 =100 in the y-direction

so, let's use the equation:

D^2 = 10^2 + 100^2

= D= sqrt*(10 + 100)

Lets use 2DD' = 2xx' + 2yy'

Differentiating with respect to t we have:

D•d(D)/dt = -(10)•dx/dt + 100•dy/dt

=100.5 d(D)/dt = (-10)•35 + (100)•25

When t=4, we have x=(140-150) =10 and y=100

= D = sqrt*(10^2 + 100^2)

=100.5

= 100.5 dD/dt = 10.35 +100.25

= dD/dt = 21.29km/h

7 0
3 years ago
A race car drives one lap around a race track that is 500 meters in length.
DIA [1.3K]

Answer:

a) 0

Explanation:

A) since he is going around a race track, his initial position is 0m, and his ending position is also 0m, so his displacement is 0. Yes, his distance is 500m, but his displacement is 0, and he did not end up going anywhere for his final position.

B) Distance is total amount traveled, which in this case is 500m, but displacement is 0 as he did not change his position.

4 0
3 years ago
. Which of the following would be the best technique to use in order to separate an insoluble solid from a liquid?. Answer. . ch
kvasek [131]
The best technique to separate an insoluble solid from a liquid is filtration. Filtration is a process that separates solids from liquid by adding a medium, such as a filter paper, that only liquid can pass, and what is left behind the filter paper is the insoluble solid.
8 0
3 years ago
Read 2 more answers
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