Answer:
where are the expressions??
Since there are 22 participants all in all. The possible combinations of the two picked for practice first is,
22C2 = 231
The probability of picking one from each gender will be solved through the calculation below.
(10C1)x(12C1) / 231 = 40/77
In percentage, the answer would be approximately 52%. Thus, the answer is the first choice.
Let's represent h with the number of hours:
15h ≥ 200
h ≥ 200/15
h ≥ 40/3
h ≥ 13 1/3
He has to work at least 13 1/3 hours.
When I look at a problem like this, I think of the FOIL method. This method states "You multiply integers in the order of First, Outside, Inside, Last, and then add them together"
(a -3b)(2a - 5b)
First --- 2a * a
Out --- (-5b) * a
In --- (-3b) * 2a
Last --- (-3b) * (-5b)
2a² - 5ab -6ab + 15b²
2a² - ab + 15b²
This would be your answer in simplest form!
