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Luda [366]
3 years ago
12

What is the percent of change from 70 to 14?

Mathematics
1 answer:
Tom [10]3 years ago
4 0

Answer: -80%

Step-by-step explanation:

((y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

((14 - 70) / 70) * 100 = -80 %

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For which of the following is x = -5 a solution? Select all that apply.
ser-zykov [4K]

Answer:

b. -x^2 + 50 = 25

c. |2x| = 10

d. x < 0

e. 2x < 10

Step-by-step explanation:

x = -5

-(-5)² + 50

-25 + 50 = 25

|2(-5)| = |-10| = 10

-5 < 0

2(-5) = -10 < 10

8 0
3 years ago
Currently, you have made a
aleksandr82 [10.1K]

Answer:

84

Step-by-step explanation:

4 test grades with an average of 80 would have a total of 80x4=320.

75+83+78=236

320-236=84

5 0
4 years ago
PLEASE ANSWER ASAP!!!!!!!!!!!
Zanzabum

Answer:

the surface area is 24

Step-by-step explanation:

there are 6 squares with area of 4 so 4 x 6 is 24

8 0
3 years ago
Read 2 more answers
Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
ankoles [38]

Option C:

2 g^{3}-5 g^{2}+6

Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

8 0
3 years ago
Read 2 more answers
3. If the line tangent to the graph of the function f at the point (1,7) also passes through the point
Usimov [2.4K]

Answer:

f'(-1)= 3

Step-by-step explanation:

slope = (y2 - y1)/(x2 - x1)= (7-(-2))/(1-(-2))=9/3=3

Slope of the tangent line in the given point equals f' at this point.

So,

f'(-1)= 3

5 0
3 years ago
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