Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
B
Step-by-step explanation:
Rate, in this case, is mph which can be written as miles/hours.
HTH :)
Answer:
yes it represents the graph accurately
Step 
<u>Find the irreducible fraction in each ratio</u>
<u>case 1)</u> 
Divide by
boths numerator and denominator

<u>case 2)</u> 
Divide by
boths numerator and denominator

<u>case 3)</u> 
Divide by
boths numerator and denominator

<u>case 4)</u> 
Divide by
boths numerator and denominator

<u>case 5)</u> 
Divide by
boths numerator and denominator

<u>case 6)</u> 
Divide by
boths numerator and denominator

<u>case 7)</u> 
Divide by
boths numerator and denominator

<u>case 8)</u> 
Divide by
boths numerator and denominator

<u>case 9)</u> 
Divide by
boths numerator and denominator

<u>case 10)</u> 
Divide by
boths numerator and denominator

<u>case 11)</u> 
Divide by
boths numerator and denominator

<u>case 12)</u> 
Divide by
boths numerator and denominator

Step 
<u>Sort the ratios into bins</u>
1<u>) First Bin</u>
<u>
</u>



<u>2) Second Bin </u>
<u>
</u>


<u>3) Third Bin</u>



4<u>) Fourth Bin</u>
<u>
</u>



