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kifflom [539]
2 years ago
8

Plsss helppppppp will give you alot of pointss

Chemistry
1 answer:
yanalaym [24]2 years ago
5 0
The answer B The sound is being diffracted around the corners of the doorway
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A sample of hydrated cobalt (II) chloride has a mass of 5.22 g. After heating, it has a mass of 2.85 g. What is the percent by m
Tom [10]
Answer:
mass of water in hydrate = 2.37 grams

Explanation:
The mass of the hydrated cobalt (III) chloride is the summation of the salt and the water it contains.
This means that:
Total mass of sample = mass of salt + mass of water

Now, we are given that:
total mass of sample = 5.22 grams
mass of salt = mass of sample after heating = 2.85 grams

Substitute to get the mass of water as follows:
5.22 = mass of water in hydrate + 2.85
mass of water in hydrate = 5.22 - 2.85
mass of water in hydrate = 2.37 grams

Hope this helps :)
5 0
2 years ago
Read 2 more answers
WILL MARK BRAINLY
DENIUS [597]

Answer:

its B i guess

Explanation:

7 0
2 years ago
Help ASAP need help and thank you:)
Akimi4 [234]

Answer:

50 N

Explanation:

Because It not in motion means it standing still. So the answer is 50 Newton

4 0
2 years ago
Calculate how many moles of nh3 form when each quantity of reactant completely reacts?
anygoal [31]

3.6 moles NH_{3} required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

3N_{2} H_{4}(l) → 4NH_{3}(g) + N_{2}(g)

Given is = 2.6 mol N_{2} H_{4}

As we see, 3 moles of N_{2} H_{4} reacts with  4 moles of NH_{3}.

Therefore,

n( NH_{3}) = n(  N_{2} H_{4} ) × \frac{4}{3}

n( NH_{3}) = 2.6mol^{*} \frac{4mol}{3mol}

n( NH_{3}) = 3.6 moles.

Therefores, 3.6 moles NH_{3} required when each quantity of reactant completely reacts.

Learn more about moles here;

brainly.com/question/20486415

#SPJ4

6 0
1 year ago
In a 0.25 M solution of HA (a weak acid), 1.0 % if the HA is ionised.
aniked [119]

Answer:

dunno

Explanation:

4 0
2 years ago
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