Answer:
Partial pressure of He = 73 kPa
Explanation:
Given:
Total pressure = 125 kPa
Partial pressure of Ne = 31 kPa
Partial pressure of Kr = 21 kPa
Find:
Partial pressure of He
Computation:
Total pressure = Partial pressure of Ne + Partial pressure of Kr + Partial pressure of He
125 kPa = 31 kPa + 21 kPa + Partial pressure of He
Partial pressure of He = 73 kPa
Answer:
This done such that when a reaction is in equilibrium and disturb by and external force which would prevent its completion its adjust so as to offset that external force and still go on to completion
Answer:
14175 j heat released.
Explanation:
Given data:
Mass of aluminium = 350.0 g
Initial temperature = 70.0°C
Final temperature = 25.0°C
Specific heat capacity of Aluminium = 0.9 j/g.°C
Heat changed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Heat change:
ΔT = Final temperature - initial temperature
ΔT = 25.0°C - 70°C
ΔT = -45°C
Q = m.c. ΔT
Q = 350 g × 0.9 j/g.°C × -45°C
Q = -14175 j
Answer:
Probably A.
Explanation:
Its either A or C. A is more probable imo
