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3241004551 [841]
3 years ago
7

If 120 g of NaOH is dissolved in 2.5 L of water, what is the molarity of the solution?

Chemistry
1 answer:
klio [65]3 years ago
8 0

Answer:

1.2 M.

Explanation:

<em>Molarity is the no. of moles of solute in a 1.0 L of the solution.</em>

M = n/V.

<em>M = (mass/molar mass)solute x (1000/V of the solution).</em>

mass of NaOH = 120.0 g.

molar mass of NaOH = 40.0 g/mol.

V of the solution = 2.5 L = 2500.0 mL.

<em>∴ M = (mass/molar mass)solute x (1000/V of the solution)</em> = (120.0 g / 40.0 g/mol) x (1000 / 2500.0 mL) = <em>1.2 M.</em>

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luda_lava [24]

Answer:

[NO] = 1.72 x 10⁻³ M.  

Explanation:

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<em>2NO(g) ⇌ N₂(g)+O₂(g),</em>

Kc =  [N₂][O₂] / [NO]².

  • At initial time: [NO] = 0.171 M,  [N₂] = [O₂] = 0.0 M.
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∵ Kc =  [N₂][O₂] / [NO]².

∴ 2400 = x² / (0.171 - 2x)² .

<u><em>Taking the aquare root for both sides:</em></u>

√(2400) = x / (0.171 - 2x)  

48.99 = x / (0.171 - 2x)  

48.99 (0.171 - 2x) = x  

8.377 - 97.98 x = x

8.377 = 98.98 x.

∴ x = 8.464 x 10⁻².

<em>∴ [NO] = 0.171 - 2(8.464 x 10⁻²) = 1.72 x 10⁻³ M.  </em>

<em>∴ [N₂] = [O₂] = x = 8.464 x 10⁻² M.</em>

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3 years ago
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Answer:

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Explanation:

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This eliminates answers C, D and E.

So we are left with A and B

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Hi there,

I hope you and your family are staying safe and healthy!

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Please leave 5 stars and a like if you find this answer helpful!

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