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3241004551 [841]
2 years ago
7

If 120 g of NaOH is dissolved in 2.5 L of water, what is the molarity of the solution?

Chemistry
1 answer:
klio [65]2 years ago
8 0

Answer:

1.2 M.

Explanation:

<em>Molarity is the no. of moles of solute in a 1.0 L of the solution.</em>

M = n/V.

<em>M = (mass/molar mass)solute x (1000/V of the solution).</em>

mass of NaOH = 120.0 g.

molar mass of NaOH = 40.0 g/mol.

V of the solution = 2.5 L = 2500.0 mL.

<em>∴ M = (mass/molar mass)solute x (1000/V of the solution)</em> = (120.0 g / 40.0 g/mol) x (1000 / 2500.0 mL) = <em>1.2 M.</em>

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Calculate the number of C, H, and O atoms in 1.50 g of glucose, a sugar
DIA [1.3K]
Chemical formula of the glucose: C₆H₁₂O₆

We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u

atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol


2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g----------------------  x

x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles

we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)

3)We calculate the number of molecules:

Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles--------        x

x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.

4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²

number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .

number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²

Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
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3 years ago
Differ B/w reducing and oxidizing smog?
aleksklad [387]

Answer:

Smog can be classified as two types. They are

Oxidizing smog

Reducing smog

Oxidizing smog:

The smog which has the property of high concentration of oxidizing agents is known as oxidizing smog. Oxidizing smog can also known as photochemical smog.

Example: Ozone.

Reducing smog:

The smog which has high concentration of sulfur Dioxide is known as reducing smog.Photochemical smog which is very dangerous is called oxidizing smog because it consists of the oxidizing agent ozone.......the other one is reducing smog which consists of reducing agent sulphurdioxide.

6 0
2 years ago
PLEASE HELP this is physical science.
Andru [333]

Bone age : 22,920 years

<h3>Further explanation</h3>

Given

Nt = 2.5 g C-14

No = 40 g

half-life = 5730 years

Required

time of decay

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Input the value :

\tt 2.5=40.\dfrac{1}{2}^{t/5730}\\\\\dfrac{2.5}{40}=\dfrac{1}{2}^{t/5730}\\\\(\dfrac{1}{2})^4=\dfrac{1}{2}^{t/5730}\\\\4=t/5730\rightarrow t=22920~years

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Answer:

The answer will be A

Explanation:

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Which of these is an indication that a chemical reaction has occurred?
lilavasa [31]

D. a change in color of a substance

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2 years ago
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