If 120 g of NaOH is dissolved in 2.5 L of water, what is the molarity of the solution?
1 answer:
Answer:
1.2 M.
Explanation:
<em>Molarity is the no. of moles of solute in a 1.0 L of the solution.</em>
M = n/V.
<em>M = (mass/molar mass)solute x (1000/V of the solution). </em>
mass of NaOH = 120.0 g.
molar mass of NaOH = 40.0 g/mol.
V of the solution = 2.5 L = 2500.0 mL.
<em>∴ M = (mass/molar mass)solute x (1000/V of the solution) </em> = (120.0 g / 40.0 g/mol) x (1000 / 2500.0 mL) = <em>1.2 M. </em>
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Answer:
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