Would you predict that the C−O bond lengths in the formate ion would be longer or shorter relative to those in CO2?
1 answer:
The Lewis structures for formate ion and carbon dioxide are shown in the attached pictures. As you can see, the formate ion consists of one C=O bond and one C-O bond, while carbon dioxide has two C=O bonds. Double bonds are weaker, hence, longer compared to single bonds. Therefore, the C-O bonds in the formate ion is shorter than those in carbon dioxide.
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<h3>Answer:</h3>
1257.45 L
<h3>Explanation:</h3>We are given;
- Initial volume of Helium gas, V1 as 806 L
- Initial temperature of Helium gas,T1 as 20.9°C
- Initial pressure of Helium gas, P1 as 753 mmHg
- Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
- Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C
But, K = °C + 273.15
Therefore, T1 = 294.05 K and T2 = 254.05 K
- We are required to calculate the new volume of the balloon at 6.8 km.
- To determine the new volume we are going to use the combined gas law.
- According to the combined gas law,
Thus, rearranging the formula;
Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L