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3 years ago

9. When making a circuit, why is gold wiring not used?

Physics

1 answer:

daser333 [38]3 years ago

4 0

Answer:

Gold is not used for making electric wires because it is too rare, and too costlier than Copper. Silver and copper are used for making wires. Copper is almost used in electric lines

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if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?

LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

The complete question is written below:

In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of $1.80 m/s^{2}$ , it would go from rest to its top speed in 85.6 s.

a) What was the speed of the vessel?

b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute?

Calculate the answers in both meters per second and kilometers per hour

a) The average acceleration $a_{av}$ is expressed as:

$a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t}$ (1)

Where:

$a_{av}=1.80 m/s^{2}$

$\Delta V$ is the variation of velocity in a given time $\Delta t$ , which is the difference between the final velocity $V$ and the initial velocity $V_{o}=0$ (because it starts from rest).

$\Delta t=85.6 s$

Isolating $V$ from (1):

$V=a_{av}\Delta t + V_{o}$ (2)

$V=(1.80 m/s^{2})(85.6 s) + 0 m/s$ (3)

$V=154.08 \frac{m}{s}$ (4)

If $1 km=1000m$ and $1 h=3600 s$ then:

$V=154.08 \frac{m}{s}=554.68 \frac{km}{h}$ (4)

b) Now we need to find the final velocity when $\Delta t=1 min=60 s$ :

$V=(1.80 m/s^{2})(60 s) + 0 m/s$ (5)

$V=108 \frac{m}{s}=388.8 \frac{km}{h}$ (6)

5 0

3 years ago

Example of a static balance

Rufina [12.5K]

Ability to maintain ones balance when not moving.

5 0

3 years ago

Light travels 186,282 miles in one second. A light year is the distance light travels in one year. It is about 4.3 light years t

deff fn [24]

Answer:

$2.5278035226\times 10^{13}\ miles$

1994.7944465 miles

46390568.5227 miles

125 ft

Explanation:

$1\ ly=186282\times 365.25\times 24\times 60\times 60=5.8786128432\times 10^{12}\ mi$

$4.3\ ly=4.3\times 5.8786128432\times 10^{12}=2.5278035226\times 10^{13}\ miles$

The distance is $2.5278035226\times 10^{13}\ miles$

$2000\ miles=0.01\ in$

$2.5278035226\times 10^{13}\times \dfrac{1}{2000}=1.2639017613\times 10^{10}\ LA\ to\ NY$

Converting to inches

$1.2639017613\times 10^{10}\times 0.01=126390176.13\ in/LA\ to\ NY$

Converting to miles

$126390176.13\times\dfrac{1}{5280\times 12}=1994.7944465\ inches/LA\ to\ NY$

The distance is 1994.7944465 miles

$5.8786128432\times 10^{17}\times \dfrac{1}{2000}\times 0.01\times\dfrac{1}{5280\times 12}=46390568.5227\ miles$

The distance is 46390568.5227 miles

$5.8786128432\times 10^{12}\times 15\times 10^{9}=8.8179192648\times 10^{22}$

$8.8179192648\times 10^{22}\times \dfrac{1}{5.8786128432\times 10^{17}}=150000\ MW\ dia$

$150000\dfrac{1}{100\times 12}=125\ ft$

The distance is 125 ft

5 0

4 years ago

Find the half-life of a radioactive material if after 1 year 99.67% of the initial amount remains. (Round your answer to one dec

Svetradugi [14.3K]

Answer:

209.68 years

Explanation:

Let T be the half life.

t = 1 year

N = 99.67 % of No = 0.9967 No

Use the law of radioactivity

N = No x e ^(- λ t)

Where, λ is decay constant.

λ = 0.6931 / T

So,

0.9967 No = No x e^(- λ t)

0.9967 = e^(- λ t)

e^( λ t) = 1 / 0.9967 = 1.0033

λ t = 3.3 x 10^-3

(0.6931 x 1) / T = 3.3 x 10^-3

T = 209.68 years

Thus, the halflife is 209.68 years.

3 0

3 years ago

The law of reflection says that the angle of incidence is

nekit [7.7K]

The law of reflection states that the angle of incidence is equal to the angle of reflection. Furthermore, the law of reflection states that the incident ray, the reflected ray and the normal all lie in the same plane.

hope this helps :)

4 0

3 years ago