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ruslelena [56]
3 years ago
14

Why is a camera lens round but the pictures come out square

Physics
2 answers:
zepelin [54]3 years ago
8 0
In addition to maintaining the traditional shape of film, using a rectangular sensor also leads to better pictures. A round camera lens does produce a round image inside the camera. ... This is because light must be bent more to reach the outer edges of the circular image.

First, it’s a known fact while lenses capture an image throughout the circumference of the glass, any degradation occurs on the outer parts of the image, hence cutting off those parts results in a sharper overall image in a rectangular format. This leads to the next question, “Then why aren’t images square?”

Another good question as it makes sense to trim off the degradation equally from all sides, which results in a square. However, any designer will tell you that a rectangle is more pleasing to the eye, since we tend to naturally see more through our own eyes in a horizontal format. This rectangle format also allows us to shoot the more powerful vertical.

Though there have been square format cameras in the past, like the Kodak 126 Instamatic camera, basically a squared 35mm format, and the more commonly known amongst professional photographers was the medium format, 2¼ square format.

I myself used the square format back in high school as a photographer. The camera of choice for my photojournalism instructor for his photographers was the Yashica Mat 120G medium format camera. The square image the camera produced was 2 ¼-inches square on each side, many times larger than a 35mm negative, allowing us ample room to crop out rectangle images in either a horizontal or vertical format.

So the more I thought about that question, I decided to come up with some answers of my own (in a humorous way) and a few other questions I’d love to know about the answers myself. So first, here are a few of my assumptions on why we capture in a rectangular format vs. a round format, though we use round lenses:

• Rectangle lenses would provide lens barrels that would be difficult to focus. Imagine turning a rectangle, focusing ring, not to mention attaching rectangle filters.

• Finding picture frames would become interesting, now we’d have different circumference size frames.

•  There would be tons of paper waste because paper is in a rectangular format, so round prints would create a non-green environment.

• Round computer monitors to view photos doesn’t make sense.

• It becomes difficult to properly align round images in frames and hang them exactly the way they were captured.

•  If video adopted round formats, tubeless televisions today but appear as one large tube.

• Our smart phones would become round to view the images properly too. Now can you imagine round Instagram photos instead of their current square format? Even worse, if you dropped your phone can you picture it rolling down hill?

• Billboards would become round adding a tunnel vision perception.

• If theater screens were round would we be sitting in tunnels viewing movies instead of rectangular theater rooms? Can you imagine the acoustics alone?

• The Rule of Thirds would require a revision.

Now here are some of my questions about other things in life:

• Why is bacon in the U.S. cut in rectangular strips and Canadian bacon in round pieces?

sergey [27]3 years ago
6 0
It is round or say spherical to widen the range of photography and it is designed to focus the image as the ray are coming from infinity so !!

I am not an expert of camera but ya it is the main theme !!
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A football is thrown due north across a 40 meter river and it takes 2 seconds to cover that distance.
Alexxx [7]

Answer:

I. Speed = 20m/s

II. Velocity = 20m/s due North.

Explanation:

<u>Given the following data;</u>

Distance = 40m

Time = 2secs

To find the speed;

Mathematically, speed is given by the formula;

Speed = \frac{distance}{time}

Substituting into the equation, we have;

Speed = \frac{40}{2}

<em>Speed = 20m/s.</em>

In physics, we use the same formula for calculating speed and velocity. The only difference is that speed is a scalar quantity and as such has magnitude but no direction while velocity is a vector quantity and as such it has both magnitude and direction.

Velocity = \frac{distance}{time}

<em>Therefore, the velocity is 20m/s due North</em>.

6 0
3 years ago
Currently, the Sun is thought to be located in the galactic _____________ about ____________ the center of the galaxy.
Ede4ka [16]

Answer:

a. Disk, 28 thousand light-years from

Explanation:

Since, a galactic disc is a component of disc galaxies, for instance spiral galaxies and lenticular galaxies. It consists of a stellar component and a gaseous component.

Also, the Sun lies within the galactic disk or in other words it is thought to be located in the galactic disk,

The Sun is located about 26,000 light-years away from the centre of the galaxy.

∵ From the given options 28,000 is nearest to 26,000

Hence, the sun is about 28 thousand light-years from the centre of the galaxy.

i.e. OPTION 'a' would be correct.

8 0
3 years ago
Assuming both graduated cylinders are holding water at room temperature, which cylinder has more thermal energy?
natta225 [31]

Answer:

The correct option is;

The graduate cylinder with more water has more thermal energy because it is holding more water molecules

Explanation:

Given that the thermal energy of the system is the energy possessed by the system by virtue of the increased motion of the particles by virtue of a transfer  of heat, when the content of the system is heated

The thermal energy, Q is given by the following equation;

Q = Mass, m × The specific heat capacity, C × The change in temperature, ΔT

Given that the graduated cylinder with more water has more mass and therefore, more water molecules, than the cylinder with less water, the cylinder with more water has more thermal energy.

3 0
3 years ago
Need 3 examples of unbalanced forces
jarptica [38.1K]
1. pulling tug of war
2. monkey swinging from vine
3. arm wrestle
4 0
3 years ago
Read 2 more answers
A mass is oscillating with amplitude A at the end of a spring.
Dmitry_Shevchenko [17]

A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

K=E-U

we can write

E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

3 0
3 years ago
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