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ruslelena [56]
3 years ago
14

Why is a camera lens round but the pictures come out square

Physics
2 answers:
zepelin [54]3 years ago
8 0
In addition to maintaining the traditional shape of film, using a rectangular sensor also leads to better pictures. A round camera lens does produce a round image inside the camera. ... This is because light must be bent more to reach the outer edges of the circular image.

First, it’s a known fact while lenses capture an image throughout the circumference of the glass, any degradation occurs on the outer parts of the image, hence cutting off those parts results in a sharper overall image in a rectangular format. This leads to the next question, “Then why aren’t images square?”

Another good question as it makes sense to trim off the degradation equally from all sides, which results in a square. However, any designer will tell you that a rectangle is more pleasing to the eye, since we tend to naturally see more through our own eyes in a horizontal format. This rectangle format also allows us to shoot the more powerful vertical.

Though there have been square format cameras in the past, like the Kodak 126 Instamatic camera, basically a squared 35mm format, and the more commonly known amongst professional photographers was the medium format, 2¼ square format.

I myself used the square format back in high school as a photographer. The camera of choice for my photojournalism instructor for his photographers was the Yashica Mat 120G medium format camera. The square image the camera produced was 2 ¼-inches square on each side, many times larger than a 35mm negative, allowing us ample room to crop out rectangle images in either a horizontal or vertical format.

So the more I thought about that question, I decided to come up with some answers of my own (in a humorous way) and a few other questions I’d love to know about the answers myself. So first, here are a few of my assumptions on why we capture in a rectangular format vs. a round format, though we use round lenses:

• Rectangle lenses would provide lens barrels that would be difficult to focus. Imagine turning a rectangle, focusing ring, not to mention attaching rectangle filters.

• Finding picture frames would become interesting, now we’d have different circumference size frames.

•  There would be tons of paper waste because paper is in a rectangular format, so round prints would create a non-green environment.

• Round computer monitors to view photos doesn’t make sense.

• It becomes difficult to properly align round images in frames and hang them exactly the way they were captured.

•  If video adopted round formats, tubeless televisions today but appear as one large tube.

• Our smart phones would become round to view the images properly too. Now can you imagine round Instagram photos instead of their current square format? Even worse, if you dropped your phone can you picture it rolling down hill?

• Billboards would become round adding a tunnel vision perception.

• If theater screens were round would we be sitting in tunnels viewing movies instead of rectangular theater rooms? Can you imagine the acoustics alone?

• The Rule of Thirds would require a revision.

Now here are some of my questions about other things in life:

• Why is bacon in the U.S. cut in rectangular strips and Canadian bacon in round pieces?

sergey [27]3 years ago
6 0
It is round or say spherical to widen the range of photography and it is designed to focus the image as the ray are coming from infinity so !!

I am not an expert of camera but ya it is the main theme !!
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A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with ne
gregori [183]

Answer:

The ball experiences the greater momentum change

Explanation:

The momentum change of each object is given by:

\Delta p = m \Delta v= m (v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

Both objects have same mass m and same initial velocity u. So we have:

- For the ball, the final velocity is

v=-u

Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is

\Delta p=m(v-u)=m((-u)-u)=-2mu

- For the clay, the final velocity is

v=0

since it sticks to the wall. So, the change in momentum is

\Delta p = m(v-u)=m(0-u)=-mu

So we see that the greater momentum change (in magnitude) is experienced by the ball.

3 0
3 years ago
When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the
MaRussiya [10]

Answer:

(a) \alpha=-111.26rad/s

(b) s=4450.6in

(c) 8.66in

Explanation:

First change the units of the velocity, using these equivalents 1rev=2\pi rad and 1 min =60s

4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s

The angular acceleration \alpha the time rate of change of the angular speed \omega according to:

\alpha=\frac{\Delta \omega}{\Delta t}

\Delta  \omega=\omega_i-\omega_f

Where \omega_i is the original velocity, in the case the velocity before starting the deceleration, and \omega_f is the final velocity, equal to zero because it has stopped.

\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s

b) To find the distance traveled in radians use the formula:

\theta = \omega_i t + \frac{1}{2} \alpha t^2

\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad

To change this result to inches, solve the angular displacement \theta for the distance traveled s (r is the radius).

\theta=\frac{s}{r} \\s=\theta r

s=890.12(5)=4450.6in

c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:

\frac{890.12}{2\pi}=141.6667

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance  between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle \gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120 is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which  is also the net displacement):

c^2=a^2+b^2-2abcos(\gamma)

c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in

4 0
4 years ago
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
3 years ago
A car interior is heated to 48 C by the sun What type of energy transfer?
Aneli [31]

Answer:

Radiation heat energy transfer

Explanation:

The type of heat transfer from the Sun is radiation heat transfer, which is the transfer of heat through electromagnetic radiation

The distance of the Sun to the Earth is several million kilometers away, with the space between being composes of vacuum and the nuclear reaction in the Sun's core generates vast amount of electromagnetic radiation that is transferred all across the universe and reaches the Earth as visible light and radiant energy at the speed of light

The radiant energy transferred from the Sun heats up the Earth, including the car's interior.

7 0
3 years ago
A 2.00-kg block of ice is moving on a frictionless horizontal surface. At t = 0 the block is moving to the right with a velocity
enyata [817]

Answer:

Explanation:

a )

We shall apply the concept of impulse .

Impulse = force x time = change in momentum

= 5 x 4 = 2 ( V - 3 )  , where V is final velocity of the object

20 = 2V - 6

V = 13 m /s

b )

Impulse applied = - 7 x 4 = - 28 kg m/s ( negative as direction of force is opposite motion )

If v be the final velocity

2 x 3 - 28 = 2 v  ( initial momentum - change in momentum = final momentum )

- 22 = 2v

v = - 11 m /s

object will move with 11 m /s in opposite direction .

4 0
3 years ago
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