Question

Please help, I don't know the formulas to do these and I'd like to know HOW y'all get the answers...thank you so much.

Answer 1

The vapour pressure in the water flask is 23.686 torr.

The pressure of $H_2$ in the flask was 713.514  torr.

Pressure is the $H_2$ exerting in the flask is 688.314 torr

What is vapour pressure?

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

a.The vapour pressure of water is given by:

$Log_{10} P =A- \frac{B}{C+T}$, where T is in degree Celcius, P is in torr.

For 0-100 degree celcius, A=8.07131, B=1730.63, C=233.426

$Log_{10} P = 8.07131 - \frac{1730.63}{233.426+25} =1.3745$

As T =25 degree celcius

$P = 10^{1.3745} torr$ =23.686 torr

b.We know that $P_{total} =P_{H_2} + P_{H_2O}$

$P_{total}$ = Atmospheric pressure

$737.2 torr = P_{H_2} +23.686 torr$

$P_{H_2} = 713.514 torr$

c.After there is a leak in the gas collection tube, the amount at pressure due to water vapour remains unchanged as it is a quantity dependent on temperature.

$P_{total} =P_{H_2} + P_{H_2O} + P_{leaking \;air}$

$737.2 torr = P_{H_2} + 23.686 torr + 25.2 torr$

$P_{H_2} =688.314 torr$

For calculating molar mass of any gas:

M= Density X (RT ÷ P)

M= 0.714 g X ($8.314 J mol^{-1}K^{-1}$273 K ÷ 101325 Pa)

M= 15.994 g/mol = 16 g/mol.

Learn more about vapour pressure here:

brainly.com/question/15740895

#SPJ1