a) Net result of Tamiko's transactions = $143.75
b) Total amount she can save = $86.25
Step-by-step explanation:
Step 1 :
Given,
Amount Tamiko got in her first check = $109.60
Amount of the bonus check = $34.15
Fraction of the amount she wants to save = 
We need to find the net results of her transactions and the amount she will save
Step 2 :
The new result of her transactions can be computed by adding the amount she has received through both the check.
Total amount she received = 109.60 + 34.15 = 143.75
Total amount she can save =
× 143.75 = 86.25
Step 3 :
Answer :
a) Net result of Tamiko's transactions = $143.75
b) Total amount she can save = $86.25
Answer:
1,038 in2
Step-by-step explanation:
In a regular hexagon, the radius and side length are equal in length... That makes the answer 1038 in.2 correct?
Answer:
60 different meal packages are possible.
Step-by-step explanation:
Fundamental counting principle:
States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.
In this question:
4 types of drinks
5 types of sandwiches.
3 types of chips.
They are independent events, so, by the fundamental counting principle:
4*5*3 = 60
60 different meal packages are possible.
Answer:

Step-by-step explanation:
To solve this, we are using the average rate of change formula:

where
is the average rate of change
is the first point
is the second point
is the function evaluated at the first point
is the function evaluated at the second point
We want to know the average rate of change of the function
form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words,
and
.
Replacing values







We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is 
Answer: 
Step-by-step explanation:
Given : The probability of a correct classification of any part is : p=0.96
sample size : n= 3
The formula to find the mean and variance for binomial distribution is given by :-

Let the random variable X denote the number of parts that are correctly classified.
The, for the given situation, we have

Hence, the mean and variance of X are 2.88 and 0.115 respectively.