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Novay_Z [31]
3 years ago
7

Simplest form 7/8 - 1/6

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0

Answer: i think it is 17/24

Step-by-step explanation:

Tresset [83]3 years ago
4 0

Answer:

17/24

Step-by-step explanation:

hope this helped:)

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Tanisha was asked to write an example of a linear relationship she wrote this my dog sitting service charges an initial $8.00 fe
stich3 [128]
1.    15.50
2. 23.00
3. 30.50
4. 38.00

5 0
3 years ago
Express the ratio as a fraction in simplest form 18 oz to 3 cups
valentinak56 [21]

Answer:

6/1

Step-by-step explanation:

Both 18 and 3 can be divided by 3

18 divided by 3 = 6

3 divided by 3 = 1

So the ratio is 6 : 1

So the fraction is 6/1

3 0
3 years ago
Read 2 more answers
5yr is how many days
Karolina [17]
There are 1,826 days in 5 yr. In relation to the leap year, there are 1826.25 days in 5 yrs. That is because there are really 365.25 days in a year (making every four years a leap year). So, when you multiply 365.25 by 5, you get 1826.25. 
6 0
3 years ago
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Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between
ivolga24 [154]

Answer:

  • 197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

  • AB = 50*2 = 100 km
  • AC = 70*2 = 140 km

The angle between AB and AC is:

  • 60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

  • BC² = AB² + AC² - 2AB*AC*cos ∠BAC
  • BC² = 100² + 140² - 2*100*140*cos 110°
  • BC²  = 39176.56 (rounded)
  • BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

7 0
2 years ago
Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
3 years ago
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