On the Periodic Table, which elements are predominantly (mostly) gases with low densities?

What is the simplified value of the exponent expression 16^1/4

Sliva [168]

Answer: 2

Justitification:

1) Property:

$a^{(1/b)} = \sqrt[b]{a}$

Therefore:

$16^{1/4}= \sqrt[4]{16}$

2) 16 = 2⁴

3) Property

$\sqrt[n]{a^n} =a^{n/n}=a$

Therefore:

$\sqrt[4]{2^4} =2^{4/4}=2$

3 0

3 years ago

Can someone please help me with this I’ll mark brainliest, in the boxes below label what level of organization might look like?

ELEN [110]

Answer:

Vascular tissue transports water, minerals, and sugars to different parts of the plant. Vascular tissue is made of two specialized conducting tissues: xylem and phloem. Xylem tissue transports water and nutrients from the roots to different parts of the plant, and also plays a role in structural support in the stem.

Explanation:

HOPE THIS HELPS!

7 0

3 years ago

The potential in an electrochemical cell, E, is related to the Gibb's free energy change (ΔG) for the overall cell redox reactio

Nana76 [90]

Answer:

Explanation:

As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)

ΔG = ΔG° + RTInQ

Q = 1

ΔG = ΔG°

ΔG = =nFE°

n=no of electrons transfered.

E° = 1.1v

ΔG° = -2 * 96500 * 1.10

= -212300J

ΔG° =-212.3kJ/mol

<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>

5 0

3 years ago

A stock solution of HNO3 is prepared and found to contain 13.1 M of HNO3. If 25.0 mL of the stock solution is diluted to a final

musickatia [10]

Answer:

The diluted solution is 0.65 M

Explanation:

Dilution formula to solve the problem is:

M concentrated . V concentrated = M Diluted . V diluted

We can also make a rule of three though.

In 1000 mL of concentrated solution, we have 13.1 moles of HNO₃

So in 25 mL we have (25 . 13.1 ) / 1000 = 0.327 moles of HNO₃

This moles are also in 0.500 L of diluted solution, the new molarity will be:

0.327 mol / 0.5L = 0.65 M

Molarity of diluted solution must be always lower than concentrated solution, otherwise the excersise is wrong.

If we replace in the formula

13.1 M . 25 mL = 500 mL . M diluted

M diluted = 13.1 m . 25 mL / 500 mL = 0.65 M

6 0

3 years ago

7.60 moles of magnesium perchlorate 3 significant figures

katen-ka-za [31]

The number of moles of Mg, Cl, and O atoms is 7.60 moles of magnesium perchlorate 7.60, 15.2, and 60.8 moles respectively.

Mole is a standard scientific unit that is used to measure large quantities of small things such as atoms, molecules, atoms, etc. A mole is the amount of a substance that contains 6.023× 10²³ particles of a substance.

The number 6.023× 10²³ is also known as the Avogadro number and is designated by the symbol $N_A$ .

The total number of atoms in every molecule of magnesium perchlorate needs to calculate. The chemical formula of the magnesium perchlorate is Mg(ClO₄)₂.

Therefore the number of atoms of magnesium, chlorine, and oxygen are 1, 2, and 8 respectively. Then, the number of moles of Mg, Cl, and O in 7.60 moles of magnesium perchlorate will be equal to :

Number of moles of Mg = 1 × 7.60 moles = 7.60 mol

Number of moles of Mg = 2 × 7.60 moles = 15.2 mol

Number of moles of Mg = 8 × 7.60 moles = 60.8 mol

Therefore, the number of moles of Mg, Cl, and O in 7.60 moles of Mg(ClO₄)₂ is 7.60, 15.2, and 60.8 moles respectively.

Learn more about the mole concept, here:

brainly.com/question/22540912

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Your question is incomplete, but most probably your full question was,

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 2.60 moles of magnesium perchlorate, mg(clo4)2. express the number of moles of Mg, Cl, and O atoms numerically, separated by commas.

6 0

1 year ago