All categories

3 years ago

Write the formulas of the acids which liberated hydrogen gas when reacting with magnesium metal

1 answer:

3 0

Mg (magnesium) reacts with acids and Produces magnesium salt and hydrogen gas as the products.
Followings are some balanced reactions of Mg with acids.

Mg(s) + H₂SO₄(aq) → MgSO₄(aq) + H₂(g)

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)

Mg(s) + 2HNO₃(aq) → Mg(NO₃)₂(aq) + H₂(g)

You might be interested in

Directions: Show all of your work for each of the following problems.

AysviL [449]

Answer:

8 0

3 years ago

What can be said about a small Ksp value?

fredd [130]

Answer:

The correct answer is option B.

Explanation:

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The equation for the ionization of the magnesium hydroxide is given as:

$A_xB_y\leftrightharpoons xA^{y+}+yB^{x-}$

xS yS

Here, S = concentration of compound dissolved in solvent via dissociation

Expression for the solubility product of $A_xB_y$ will be:

$K_{sp}=[A^{y+}]^x[B^{x-}]^y\\\\K_{sp}=(xS)^x\times (yS)^y$

As we can see,

$K_{sp}\propto [S]$

Higher the value of [S] more will be solubility of compound in a solvent.Hence, more soluble it will be.
Lower the value of [S] less will be solubility of compound in a solvent.Hence, less soluble it will be.

Hence, the correct answer is option B.

7 0

3 years ago

Help meeee!<br> 3874 dkg = _____ dg

musickatia [10]

Answer:

the answer is 387400 but I might be wrong

6 0

3 years ago

A current is applied to two electrolytic cells in series. In the first, silver is deposited; in the second, a zinc electrode is

vitfil [10]

The amount of Ag plated out if 1.2 g of Zn dissolves is 3.959 g .

Given ,

A current is applied to two electrolytic cells in series .

In the first ,silver is deposited and in the second a zinc electrode is consumed .

the reactions involving are ;

Ag+ (aq) + e = Ag

Zn = Zn2+ (aq) +2e

thus the resultant equation is ,

2Ag+ (aq) +Zn = 2Ag + Zn2+

Thus for every mole of Zn dissolves , there is 2 moles of Ag is formed .

65.38 g of Zn contains = 1 moles

1.2 g of Zn contains = 1.2/65.38 =0.01835 moles

for every 1 mole of Zn dissolves there is 2 moles of Ag formed .

Thus the amount of Ag formed in moles =2(O.01835) =0.0367 Moles

1 mole of Ag contains = 107.86g

0.0367 moles of Ag contains = 107.86 (0.0367) =3.959 g of Ag

Hence ,the amount of Ag plated out if 1.2 g of Zn dissolves is 3.959 g .

Learn more about electrolytic cell here:

brainly.com/question/19854746

#SPJ4

6 0

1 year ago

Which atom is most likely involved in the coordination of calcium ions found in hrp?.

Blizzard [7]

Answer:

oxygen

Explanation:

hope this helps

6 0

2 years ago