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Sonbull [250]
3 years ago
11

When 86.5 g of calcium chlorate decomposes into calcium chloride and oxygen, how many grams of oxygen are produced? Ca(ClO3)2 →

CaCl2 + O2
Chemistry
1 answer:
natita [175]3 years ago
8 0

Answer:

40.1 g

Explanation:

The <em>balanced equation</em> is:

  • Ca(ClO₃)₂ → CaCl₂ + 3O₂

First we <u>convert 86.5 g of calcium chlorate into moles</u>, using its<em> molar mass</em>:

  • 86.5 g Ca(ClO₃)₂ ÷ 206.98 g/mol = 0.418 mol Ca(ClO₃)₂

Then we <u>convert Ca(ClO₃)₂ moles into O₂ moles</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:

  • 0.418 mol Ca(ClO₃)₂ * \frac{3molO_2}{1molCa(ClO_3)_2} = 1.254 mol O₂

Finally we <u>convert O₂ moles into grams</u>:

  • 1.25 mol O₂ * 32 g/mol = 40.1 g O₂
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Hope this helps!

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4 years ago
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Cloud [144]

Answer:

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6 0
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2
Law Incorporation [45]

Answer:

(a) W

(b) X

(c) Y

Explanation:

Let's consider the following table with melting and boiling points for 4 substances.

Substance     Melting Point (°C)       Boiling Point (°C)

     W                       -7                                  60

     X                       660                              2500

     Y                        180                               1330

     Z                         115                                445

Let's consider that:

  • Below the melting point, a substance is solid.
  • Between the melting and the boiling point, a substance is liquid.
  • Above the boiling point, a substance is gas.

(a) Which substance is a gas at 100°C?

At 100 °C, W is above the boiling point

(b) Which substance is a liquid for the largest range of temperature?

The largest difference between the melting point and the boiling point is that of X: 2500 - 660 = 1840.

(c) Which substance is liquid at 1000 °C and a gas at 2000°C?​

Y is between the melting and the boiling point at 1000 °C and above the boiling point at 2000 °C.

3 0
3 years ago
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Answer: A) The molar amount of gas

Credit to: @Edufirst

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