v = 
and
a = 
We have acceleration and velocity so:
3 = 
88.3 = 
In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...
So...


Divide by three and
t = 29.4 s
Answer:
Distance = 70 meters
Explanation:
<u>Given the following data;</u>
Speed = 90 km/h
Time = 2.8 seconds
<u>Conversion:</u>
90 km/h to meters per seconds = 90 * 1000/3600 = 90000/3600 = 25 m/s
To find the distance covered during this inattentive period;
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the formula;
Making distance the subject of formula, we have;

Substituting into the above formula, we have;

<em>Distance = 70 meters</em>
C because the length & the path i took determines the distance .
Answer:
the rate of heat transfer after the system achieves steady state is -3.36 kW
Explanation:
Given the data in the question;
mass of water m = 50 kg
N = 300 rpm
Torque T = 0.1 kNm
V = 110 V
I = 2 A
Electric work supplied W₁ = PV = 2 × 110 = 220 W = 0.22 kW
Now, work supplied by paddle wheel W₂ is;
W₂ = 2πNT/60
W₂ = (2π × 0.1 × 300) / 60
W₂ = 188.495559 / 60
W₂ = 3.14 kW
So the total work will be;
W = 0.22 + 3.14
W = 3.36 kW
Hence total work done on the system is 3.36 kW.
At steady state, the properties of the system does not change so the heat transfer will be 3.36 KW.
The heat will be rejected by the system so the sign of heat will be negative.
i.e Q = -3.36 kW
Therefore, the rate of heat transfer after the system achieves steady state is -3.36 kW