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Ahat [919]
2 years ago
11

Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 90.0 kg, down a p slope at constant speed, as sho

wn below. The coefficient of friction between the sled and the snow is 0.100. (a) How much work is done by friction as the sled moves 30.0 m along the hill
Physics
1 answer:
kondor19780726 [428]2 years ago
5 0

The work done by friction to move the sled is  - 1,323 J.

<h3>What is Coefficient of friction?</h3>
  • The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them.
  • Typically, it is represented by the Greek letter µ. In terms of math, is equal to F/N, where F stands for frictional force and N for normal force.
  • The coefficient of friction has no dimensions because both F and N are measured in units of force (such as newtons or pounds). For both static and kinetic friction, the coefficient of friction has a range of values.
  • When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. The frictional force opposes an object's motion in kinetic friction.

Solution:

Given that

Coefficient of friction (µ) = 0.10

Mass (m) = 90kg

distance covered (d) = 30m

We use the formula:

friction work = -µmgdcos∅

friction work = -0.100 × 90 kg × 9.8 m/s² × 30 m × cos 60°

friction work = - 1,323 J

Know more about Coefficient of friction numerical brainly.com/question/19308401

#SPJ4

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Iteru [2.4K]
I believe the answer is B
7 0
3 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a −80-nC charge at x = −4 m on
disa [49]

Answer:

V = 48 Volts

Explanation:

Since we know that electric potential is a scalar quantity

So here total potential of a point is sum of potential due to each charge

It is given as

V = V_1 + V_2 + V_3

here we have potential due to 50 nC placed at y = 6 m

V_1 = \frac{kQ}{r}

V_1 = \frac{(9\times 10^9)(50 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_1 = 45 Volts

Now potential due to -80 nC charge placed at x = -4

V_2 = \frac{kQ}{r}

V_2 = \frac{(9\times 10^9)(-80 \times 10^{-9})}{12}

V_2 = -60 Volts

Now potential due to 70 nC placed at y = -6 m

V_3 = \frac{kQ}{r}

V_3 = \frac{(9\times 10^9)(70 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_3 = 63 Volts

Now total potential at this point is given as

V = 45 - 60 + 63 = 48 Volts

3 0
3 years ago
Blaine steps onto a ski slope with an angle of 25°. There is a coefficient of kinetic friction of 0.15 between him and the groun
Ymorist [56]

θ = angle of the incline surface from the horizontal surface = 25⁰

μ = Coefficient of friction = 0.15

m = mass of the person = 65 kg

f_{k} = kinetic frictional force acting on the person as he slides down

mg = weight of the person acting in down direction

F_{n} = normal force by the incline surface on the person

the free body diagram showing the forces acting on the person is given as


3 0
3 years ago
The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were obser
ELEN [110]

Answer:

a)  v² = G M R³,  b)  T = 2π /\sqrt{GMR}, c)  m \sqrt{GMR^5 }

Explanation:

a) The kinetic energy is

         K = ½ m v²

       

to find the velocity let's use Newton's second law

          F = m a

acceleration is centripetal

           a = v² / R

           

force is the universal force of attraction

           F = G m M / r²

we substitute

          G m M R² = m v² R

          v² = G M R³

           

the kinetic energy is

          K = ½ m G M R³

b) angular and linear velocity are related

          v = w R

          w = v / R

          w = \frac{\sqrt{GMR^3  }}{R}

          w = \sqrt{GMR}

the angular velocity is related to the period

          w = 2π / T

          T = 2π / w

we substitute

           T = 2π /\sqrt{GMR}

c) the angular moeomto is

            L = m v r

            L = m RA G M R³ R

            L =  m \sqrt{GMR^5 }

4 0
3 years ago
Free fall is a situation in which the only force acting upon an object is gravity. Why do all objects in free fall have the same
Angelina_Jolie [31]

free fall is a special type of motion in which the only force acting upon an object is gravity.  all objects will fall with the same rate of acceleration, regardless of their mass.

5 0
3 years ago
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