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sineoko [7]
3 years ago
11

Immature forms of many animals, like Guinea worms, before they morph into adults

Physics
2 answers:
AveGali [126]3 years ago
8 0

The immature forms of animals which they are before metamorphosis are the larva.

<u>Explanation:</u>

The larva in plural form is known as the larvae. The eggs are hatch into the form of larva. These larvae grow in different stages which are marked according to the stages as I or II and so on.

After the larval development, when they are ready to be converted into adults, metamorphosis occurs. This process changes the larva into adults. Here the immature form gets converted into mature adult form.

liberstina [14]3 years ago
6 0

Answer:

True

Explanation: If this is a true or false question it is *T*

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Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00 m away, the distance from the ce
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Answer:

\lambda= 506.25 nm

Explanation:

Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.

This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:

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y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1

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\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm

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