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Nuetrik [128]
3 years ago
13

What does this equal??

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

I think 3

Step-by-step explanation:

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14 more than the product of 59 and q<br> Write an algebraic expression
mel-nik [20]

Answer:

14+(59*q)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The volume of a rectangular prism is 7200 cubic centimeters. It has a length of 24 centimeters and a width of 20 centimeters. Wh
inessss [21]
The height of the rectangular prism is 15 centimeters

5 0
3 years ago
Can you answer this PLEASEEEE​
WINSTONCH [101]

The figure is a parallelogram so the facing sides have equal size which means :

DE = GF & DG = EF

-------------------------------------------------------------

DE = 3x - 1 , GF = 2x + 11

DE = GF ==》 3x - 1 = 2x + 11

subtract sides minus 2x

==》- 2x + 3x - 1 = - 2x + 2x + 11

collect like terms

==》 x - 1 = 11

add sides 1

==》 x - 1 + 1 = 11 + 1

==》 x = 12

-------------------------------------------------------------

As we found : DG = EF

DG = 2x - 3 So EF = 2x - 3

To find the size of EF, we need to put the value of x (which we found above) instead x.

EF = 2 × ( 12 ) - 3 ==》 EF = 24 - 3

==》 EF = 21

And we're done...

8 0
3 years ago
Estimate the isoelectric point of a ser–his dipeptide. explain why this value is only an estimate.
uranmaximum [27]
A dipeptide bond connects two amino acids. Ser stands for Serine while His stands for Histidine. Isoelectric point is when all charges of the two amino acids cancel out. This can be estimated by finding the average of the isoelectric points (pI) of the two amino acids.

Serine: pI = 5.68
Histidine: pI = 7.59

Average pI = (5.68 + 7.59)/2 =<em> 6.635

</em>
<em />This is only a rough estimate because an arithmetic average will not coincide with the biochemistry of the amino acids. The true value of the isolectric point is determined through experimentation. However, it would be more ore less around 6.635.<em>
</em>
3 0
3 years ago
Write the equation of the circle graphed below
Serjik [45]

<u>Given</u>:

Given that the circle is graphed with center (-1,1)

We need to determine the equation of the circle.

<u>Radius</u>:

To determine the radius of the circle, let us simply count the number of units between the center point to any point on the circle.

Hence, from the figure, it is obvious that there are 5 units between the center and any point on the circle.

Thus, radius of the circle is 5 units.

<u>Equation of the circle:</u>

The standard form for the equation of the circle is given by

(x-h)^{2}+(y-k)^{2}=r^{2}

where the center is (h,k) and radius is r.

Substituting the center (-1,1) and r = 5 in the above formula, we get;

(x+1)^{2}+(y-1)^{2}=5^{2}

(x+1)^{2}+(y-1)^{2}=25

Thus, the equation of the circle is (x+1)^{2}+(y-1)^{2}=25

7 0
3 years ago
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