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Tomtit [17]
3 years ago
14

In which regions can the gravitational field strength due to the two planets be zero? Explain.

Physics
1 answer:
yan [13]3 years ago
7 0

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

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Two identical charges q placed 2.0 mapart exert forces of magnitude 4.0 N on each other What is the value of the charge q? a) q
katen-ka-za [31]

Answer:

c) 4.2*10^{-5}C

Explanation:

Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:

F=\frac{kq_{1}q_{2}}{r^{2}}

where k is a proportionality constant with the value k=9*10^{9}\frac{Nm^{2}}{C^{2}}

In this case q_{1}=q_{2}=q, so we have:

F=\frac{kq^{2}}{r^{2}}

Solving the equation for q, we have:

kq^{2}=Fr^{2}

q^{2}=\frac{Fr^{2}}{k}

q=\sqrt{\frac{Fr^{2}}{k}}

Replacing the given values:

q=\sqrt{\frac{4.0N*(2.0m)^{2}}{9*10^{-9}\frac{Nm^{2}}{C^{2}}}}

q=4.2*10^{-5}C

3 0
3 years ago
. A book is moved once around the perimeter of a table of dimensions 2.00 m by 3.00 m. If the book ends up at its initial positi
Lynna [10]

Answer:

10

Explanation:

displacement would be 10 because knowledge

5 0
3 years ago
How to convert from fahrenheit to celsius
kaheart [24]
The formula for Fahrenheit and Celsius conversion is 
T(°F)<span> = </span>T(°C)<span> × 1.8 + 32
where T is temperature in F or C ( Fahrenheit or Celsius whatever is the case)
</span>This means that keeping this FORMULA in mind we can add different values to it and  accordingly convert values from one to another.
Some examples of fahrenheit conversions to Celsius are :
32°F = 0°C  using F = (0 x 1.8) + 32


8 0
3 years ago
Read 2 more answers
What is the reactive force when a fish swims through water?
natima [27]
The answer is D

This is an example of Newton's third law of motion.

The active force is the fish against the water, so the reactive force would be the reverse, the equal force of the water on the fish.
7 0
3 years ago
A child’s toy arrow is launched horizontally from a bow at a speed of 8 m/s from a second story window 4 meters above the ground
Westkost [7]
First find the time it takes to hit the sand t
using s=1/2 g t^2
t^2= 8/9.8= 0.82 seconds
This means the sand was s = 8 * 0.82 = 6.5m away
The horizontal speed stays constant at 8 m/s
The vertical speed =.82 * 9.8 = 8.0 m/s
As the two velocities are equal the angle must be 45 degrees to the horizontal
7 0
3 years ago
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