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Tomtit [17]
3 years ago
14

In which regions can the gravitational field strength due to the two planets be zero? Explain.

Physics
1 answer:
yan [13]3 years ago
7 0

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

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The greater the mass of an object
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Answer:

The greater the velocity, the greater the Force needs to be, and the greater the fiction is

Explanation:

I don't know what you are working on so here are a few responses

7 0
3 years ago
Temperature is a measure of the average ____________ energy of an object's particles. light mechanical potential kinetic
Zielflug [23.3K]
Temperature is a measure of the average kinetic energy of the particles of a substance.
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Which of these is a type of mass movement that is likely to happen after a large amount of rain
Gala2k [10]
The answer is landslide
3 0
4 years ago
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M = 15 kg, a = 2 m/s2, F =
Lisa [10]

Answer:

<h2>30 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 15 × 2

We have the final answer as

<h3>30 N</h3>

Hope this helps you

7 0
3 years ago
If an object is projected upward from ground level with an initial velocity of 144144 ft per​ sec, then its height in feet after
Liula [17]

Answer:

4.5 s, 324 ft

Explanation:

The object is projected upward with an initial velocity of

v_0 = 144 ft/s

The equation that describes its height at time t is

s(t) = -16t^2 + 144 t (1)

where t, the time, is measured in seconds.

In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):

v(t) = s'(t) = -32t +144 (2)

At the maximum heigth, the vertical velocity is zero:

v(t) = 0

Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:

0=-32t+144\\t=\frac{144}{32}=4.5 s

And by substituting this value into eq.(1), we also find the maximum height:

s(t) = -16(4.5)^2+144(4.5)=324 ft

3 0
3 years ago
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