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Tomtit [17]
3 years ago
14

In which regions can the gravitational field strength due to the two planets be zero? Explain.

Physics
1 answer:
yan [13]3 years ago
7 0

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

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A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
Vaselesa [24]

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

5 0
3 years ago
A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the
Bond [772]

Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

qvB = m\frac{v^2}{r}

where

q is the charge

v is the velocity

B is the magnetic field

m is the mass

r is the radius of the orbit

The period of the motion is

T=\frac{2\pi r}{v}

Re-arranging for r

r=\frac{Tv}{2\pi}

And substituting into the previous equation

qvB = m \frac{Tv^3}{2\pi}

Solving for T,

T=\frac{2\pi q B}{m v^2}

So we see that the period is:

- proportional to the charge and the magnetic field

- inversely proportional to the mass and the square of the speed

So the following will increase the period of the particle's motion:

Increasing its charge

Increasing the field strength

4 0
3 years ago
What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original
DIA [1.3K]

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

F=\dfrac{kq_1q_2}{r^2}

Where

q₁ and q₂ are charges

r is the distance between charges

When  each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

F'=\dfrac{kq_1'q_2'}{r'^2}

Apply new values,

F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F

So, the new force becomes 64 times the initial force.

7 0
2 years ago
Which type of force pulls objects toward one another
Klio2033 [76]
Gravity ALWAYS does that, and electrostatic force does it when two objects have opposite charges.
4 0
3 years ago
Read 2 more answers
The scientific method is a process that scientists use to understand the physical world. Place the four basic steps of the scien
prisoha [69]

Answer:

a,b,c,e,d

Explanation:

The typical approach by the scientists use to understand the physical world includes the following steps:

Identifying a Problem

Researching the Information

Stating a Hypothesis (Possible Solution)

Testing the Hypothesis

Gather Data

Analysis of the Data

Stating a Conclusion

Publishing the Result

Therefore, according to the question the correct order would be:

a. Observation of physical world.

b. Create hypothesis about observation.

c. Test consequences of hypothesis

e. Adjust results to agree with popular opinion

d. Report outcome

5 0
3 years ago
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