<u><em>Answer:</em></u>
<u><em>Explanation:</em></u>
<u>Part 1: Solving for m</u>
<u>We are given that:</u>
E = mc²
To solve for m, we will need to isolate the m on one side of the equation
This means that we will simply divide both sides by c²
<u>Part 2: Solving for c</u>
<u>We are given that:</u>
E = mc²
To solve for c, we will need to isolate the m on one side of the equation
This means that first we will divide both sides by m and then take square root for both sides to get the value of c
<u>Part 3: Solving for E</u>
<u>We are given that:</u>
m = 80 and c = 0.4
<u>To get the value of E, we will simply substitute in the given equation: </u>
E = mc²
E = (80) × (0.4)²
E = 12.8 J
Hope this helps :)
- Increase in melting point;
- Trans- arrangements of side chains around double bonds that remains in the hydrogenated fat.
Explanation:
Vegetable oil contain a larger ratio of double bonds among all its carbon-carbon bonds than animal fat such as butter does. Unlike carbon-carbon single bonds, structures connected to carbon-carbon double bonds are unable to rotate around the bonding axis. As a result, molecules rich in double bonds aren't as malleable or stack as tightly as those with a smaller number of double bonds do. The spacy molecular configuration hinders the formation of intermolecular forces, such that in nature in comparison with animal fats, vegetable <em>oils</em> tend to demonstrate lower melting points.
Hydrogenating vegetable oils reduce the number of double bonds per molecule while attaching extra hydrogen atoms to carbon atoms that used to form double bonds. This process would increase the strength of intermolecular interaction, hence raising the melting point.
The hydrogenation process does not necessary convert <em>all</em> double bonds to single bonds; some double bonds remains in the molecule, preventing the rotation of structures on their sides. Double bonds in naturally-occuring fatty acids tend to be of the cis- configuration, with hydrogen atoms connected to the same side of the carbon-carbon double bond. The high temperature involved in the hydrogenation process (around 90 degrees Celsius) can trigger the flipping of atoms connected to these double bonds to produce trans- fatty acids with hydrogen atoms bonded to opposite sides of the double bond.
Molar mass of SnO_2:-
1 mol of SnO_2 produces 2mol of water
- 0.5mol of SnO_2 will produce 0.5(2)=1mol of water
Answer:
1
Explanation:
The empirical formula describes the simplest whole number ratio of each type of atom in a compound. To find this formula, you need to (1) convert grams of each element to moles (via their atomic masses) and then (2) find the ratio of each element (by dividing each molar value by the smallest mole value).
(Step 1)
Atomic Mass (Zn): 65.380 g/mol
Atomic Mass (C): 12.011 g/mol
Atomic Mass (O): 15.998 g/mol
10.40 grams Zn 1 mole
------------------------ x ------------------------ = 0.159 moles Zn
65.380 grams
1.92 grams C 1 mole
--------------------- x ----------------------- = 0.160 moles C
12.011 grams
7.68 grams O 1 mole
---------------------- x ------------------------ = 0.480 moles O
15.998 grams
(Step 2)
0.159 moles Zn / 0.159 = 1 atom Zn
0.160 moles C / 0.159 = 1 atom C
0.480 moles O / 0.159 = 3 atom O
The empirical formula is Zn₁C₁O₃. Therefore, the value that should be in the space is 1.
