50 g of liquid X at 10 Celcius and 200 g of liquid Y
mx*cx*(t-tx)+my*cy*(t-ty)=0
cx/cy = - my*(t-ty) : mx*(t-tx) = (my/mx) * (ty - t) / (t-tx)
cx/cy = 200/50*(40-15)/(15-10) = 20
cx/cy = 20
Answer:
The acceleration of the bag of sand is
.
Explanation:
We have,
Mass of a bag of sand is 100 kg
Weight of the bag of sand is 100 N
It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :

When it is dropped, a = g

So, the acceleration of the bag of sand is
.
Answer:
The answer is B
Explanation:
The line spectrum shows distinct light different energies and wavelengths