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3 years ago

Your mom is making lunch which forces are acting on your mom

Physics

2 answers:

N76 [4]3 years ago

7 0

The forces acting on your mom while cooking is Air resistance and the force of friction

Explanation:

1. Air resistance:

In simple words, Air resistance can be stated as the type of friction between the air and the other materials.
In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows

2. The force of friction:

In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.

Degger [83]3 years ago

6 0

When your mom is making lunch, the forces acting on your mom are gravity and normal force.

Explanation:

Gravity is the force exerted by earth on objects.The force of gravity is equal to the weight of the object. Movements or immobile positions on earth, all involves gravity and it is the gravitational force that enables you to stand still.Gravity is exerted in the downward direction.

Normal force acts on the upward direction opposite to the direction of gravity.When your mom is making lunch,gravity acts on her in the downward direction while an equal normal force acts in the upward direction.The gravity and normal force are balanced forces here.

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Answer:

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2 years ago

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2 years ago

Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.

Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

$F=\frac{\Delta p}{\Delta t}$

where

F is the force applied

$\Delta p$ is the change in momentum

$\Delta t$ is the time interval

The change in momentum can be written as

$\Delta p=m(v-u)$

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

$F=\frac{m(v-u)}{\Delta t}$

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

$\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s$

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