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bija089 [108]
3 years ago
5

A tug-of-war game is played by five c/hildren: three on one team and two on the other. How much force will the two child team ha

ve to exert against the three child team in order to hold the rope steady if the three children opposing them exert forces of 300 N, 150 N, and 50N respectively? Will the force be equally distributed between the two children?
Physics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

no, 3 porces is more tha 2 so the power between the 3 should be more than 2

Explanation:

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What are not examples of velocity
Nookie1986 [14]

Answer:

Explanation:

Acceleration roughly means “change in velocity.” If this change in velocity is consistently in one direction, the body will reach a point at which its velocity is zero.

Another consideration is when you drop a basketball onto the pavement. The ball falls, hits the ground, and comes back up. Because its direction of motion changed, you know that its velocity MUST have been 0 m/s at some point during the bounce.

This doesn't mean there was no acceleration at this point.

8 0
3 years ago
Read 2 more answers
Vector C has a magnitude of 24.6 m and points in the − y ‑ direction. Vectors A and B both have positive y ‑ components, and mak
frez [133]

Answer:

A= 61.35

B= -44.40

Explanation:

1. Using the components method we have:

A_{x}= A cos \alpha\\B_{x}= B cos \beta\\C_{x}= 0\\\\A_{y}= A sin \alpha\\B_{y}= B sin \beta\\C_{y}= 24.6\\

Considering that the vector sum A+B+C=0, then:

|V|=\sqrt{V_{x}^{2} +V_{y}^{2} }=0

Then:

V_{x} ^{2} =0; V_{x} =0\\V_{y} ^{2} =0; V_{y} =0

It means the value of x and y component is 0.

2. Determinate the equations that describe each component:

V_{x}= A cos \alpha -B cos \beta=0  (1)\\V_{y}= A sin \alpha +B sin \beta - C=0   (2)

Form Eq. (1):

A=B \frac{cos \beta}{cos \alpha}     (3)

Replacing A in Eq. (2):

(B\frac{cos \beta}{cos \alpha})(sin \alpha)+ B sin\beta-C=0\\(B\frac{cos \beta}{cos \alpha})(sin \alpha)+ B sin\beta-=C\\\\B(\frac{cos \beta. sin \alpha}{cos \alpha}+ sin\beta)=C\\B=C(\frac{cos \beta. sin \alpha}{cos \alpha}+ sin\beta)^{-1}     (4)

Replacing values of C, α and β in (4):

B= 24.6 (\frac{(cos 27.7)(sin 44.9)}{cos 44.9}+sin 27.7)^{-1}  \\B= -44.4

Replacing value of B in (3)

A=-44.40\frac{cos 27.7}{sin 49.9} \\A= 61.35

5 0
3 years ago
What is magnum effect?
iragen [17]

An observable phenomenon that is commonly associated with a spinning object moving through a fluid.

5 0
3 years ago
After a model rocket reached its maximum height, it then took 5.0 seconds to return to the launch site. what is the approximate
kifflom [539]
Air resistance is ignored.
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.

Let h =  the maximum height reached.
Let u =  the vertical launch velocity.

Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0 
u = 49 m/s

The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
   = 122.5 m

Answer: 122.5 m
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3 years ago
What does force change?
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A force is a push or pull to an object
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3 years ago
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