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2 years ago

7

A school bought 10³ erasers as part of an order for supplies. The total cost of the erasers was $30. What was the cost of each e

raser?

1 answer:

tresset_1 [31]2 years ago

8 0

Answer:

0.03

Step-by-step explanation:

divide 3 by 10^3 to obtain the answer.

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Help due soon plss!!!!

Gelneren [198K]

Answer:

Cube=150cm^2

Triangular Prism=228ft^2

Step-by-step explanation:

Cube

$A=6a^2=6*5^2=150cm^2$

Triangular prism

Using these formulas

$A=2A_{B}+(a+b+c)h\\A_{B} =\sqrt{s(s*a)(s*b)(s*c)} \\s=\frac{a+b+c}{2}$

Solving for A

$A=ah+bh+ch+\frac{1}{2} \sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4} \\=6.5*11+5*11+6.5*11+\frac{1}{2} *\sqrt{-6.5^4+2*(6.5*5)^2+2*(6.5*6.5)^2-5^4+2*(5*6.5)^2-6.5^4} \\=228ft^2$

5 0

2 years ago

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 44 o

Cerrena [4.2K]

Answer:

a) No 95% of values will fall between (24;64); 68,27% will fall between (34;54)

b)71,83 % will fall between 34 and 64 ounces

Step-by-step explanation:

Empirical rule establishes, for a normal distribution with mean μ and σ as standard deviation:

In interval μ ± σ or ( μ + σ ; μ - σ) we should find 68.27 % of all values of the population, and by simmetry 68.27/2 = 34,14 % should be over the mean and the other half would be values below the mean

Therefore in our case

μ + σ = 44 + 10 = 54

And

μ - σ = 44 - 10 = 34

a) Then 68,34 % of values will fall in this interval

We know now that value 34 is 1* σ below the mean, and is at the limit of 34,14 %

b) μ + 2*σ = 44 * 2*10 = 44 + 20 = 64

64 is the upper limit for the interval μ + 2*σ and we know that 95.45 % of all values will fall between ( μ - 2*σ ; μ + 2*σ ) and by simmetry just one side of this interval (the right side ) will have 95.45/2 = 47;73 %

Then in interval going from ( 34 ; 64 ) we shoud find 47.73 + 34,14

71,83 % of all values will fall between 34 and 64

7 0

3 years ago

Find cotθ, cosθ, and secθ, where θ is the angle shown in the figure.

Darina [25.2K]

Answer:

$\cos( \theta) = \frac{5}{8} \\ {8}^{2} = {5}^{2} + {opp}^{2} \\ {opp}^{2} = 64 - 25 = 39 \\ opp = \sqrt{39} \\ \sin(\theta) = \frac{\sqrt{39}}{8} \\ \tan(\theta) = \frac{ \sqrt{39} }{5} \\ \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{1}{\frac{ \sqrt{39} }{5}} \\ \cot(\theta) = \frac{5}{ \sqrt{39} } \\ \csc( \theta) = \frac{1}{\sin(\theta)} = \frac{1}{\frac{\sqrt{39}}{8}} \\ \csc( \theta) = \frac{8}{ \sqrt{39} } \\ \sec( \theta) = \frac{1}{\cos( \theta) } = \frac{1}{ \frac{5}{8} } \\ \sec( \theta) = \frac{8}{5}$

5 0

2 years ago

The cost of a whole box of chips are $60. I have $48. What percentage of the total cost do I have?

goblinko [34]

Answer:

Percentage of total I have = 80%

Step-by-step explanation:

Given:

Price of Box = $60

I Have = $48

To Find:

Percentage I have = ?

Solution:

In this question we are just supposed to find out the percentage of the Value we have so

Percentage can be found by the formula

Percentage $=\frac{Given Value}{Total}*100$ %

Now we have the values of all

So putting in the values

Percentage $=\frac{48}{60}*100$ %

$=\frac{4800}{60}$ %

= 80%

So the Percentage of total cost I have is 80%

Percentage of total = 80%

4 0

3 years ago

Solve the following expression when<br> t = 3 and s = 2<br> (12t) = (6s)<br> Enter

larisa86 [58]

From the solution of the expression, it can be seen that s = 6 when t = 3 while t = 1 when s = 2.

<h3>How do we solve a mathematical expression?</h3>

Given:

(12t) = (6s) ........................ (1)

When t = 3, we can solve for s from the expression in equation (1) by substituting t = 3 into the equation as follows:

12 * 3 = 6s

36 = 6s

s = 36 / 6

s = 6

When s = 2, we can solve for t from the expression in equation (1) by substituting s = 2 into the equation as follows:

12t = 6 * 2

12t = 12

t = 12 / 12

t = 1

Learn more about mathematical expression here: brainly.com/question/12401681.

#SPJ1

7 0

2 years ago