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ziro4ka [17]
3 years ago
6

Which type of graph is displayed? O line O bar O scatterplot O histogram

Physics
1 answer:
neonofarm [45]3 years ago
8 0

Answer :It is a bar graph

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Riding his bike, dewayne can start from rest and get going at 12m/s in 4 seconds. Beth can get going 16m/s in 5 seconds. Who has
sweet [91]

Answer: Beth

Explanation: Dewayne (a) = 12/4 = 3m/s^2.

Beth (a) = 16/5 = 3.2 m/s^2.

So, Beth is the answer.

5 0
3 years ago
Read 2 more answers
Is energy transformation from potential to kinetic 100%?
Arada [10]
Yes. take a bow for instance. while pulling back the string you have potential energy. when you let the string go and the arrow flies towards your target the string is filled with kinetic energy.
8 0
3 years ago
Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to
Anestetic [448]
Your answer should be D.
Hope this helps :)
5 0
3 years ago
An eartly method of measuring the speed of light makes use of a rotating slotted wheel.
Pavel [41]

Answer:

Explanation:

Distance traveled by light = 2 x 550 m = 1100 m

time taken by light to travel this distance = 1100 / 3 x 10⁸

=  366.67 x 10⁻⁸ s

angle between two consecutive slots = 2π / 500 rad

= .004π

angular velocity of wheel = angle moved / time taken

= .004π / 366.67 x 10⁻⁸

= 1091π radian / s

b )  linear speed of a point on the edge of the wheel

= ω R , r is radius of wheel , ω is angular velocity.

= 1091π x 5 x 10⁻²

= 1712.8 m /s

4 0
4 years ago
A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and
viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, m=5\ g=5\times 10^{-3}\ kg

Hanged mass in the string, m'=200\ g=0.2\ kg

1. The tension in the string is given by :

T=m'g

T=0.2\times 9.8

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

v=\sqrt{\dfrac{T}{M}}

m = M/l

v=\sqrt{\dfrac{Tl}{m}}

v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}

v = 28 m/s

Hence, this is the required solution.

4 0
3 years ago
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