How much force is required to hold an empty carton of volume 1.5 L beneath the surface in a sink of water? Assume the carton is
1 answer:
Answer:
It will require 14.715 N of force to hold the cartoon beneath the water.
Explanation:
Given the the volume of cartoon is 1.5 liters.
We need to find the force required to hold this cartoon beneath the water.
As we know from the Archimedes principle that the net force is equal to the volume of liquid displaced.
Given volume of the cartoon is 1.5 liters. So, 1.5 liters of water will be displaced.
And we know the density of the water is . That is
And
So, it will require 14.715 N of force to hold 1.5 liter volume of cartoon beneath the water.
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<h2>Hello!</h2>
The answer is: 8.62m
<h2>Why?</h2>There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.
<h2>First moment:</h2>Before the ball is thrown, where the potential energy is 0.
<h2>Second moment: </h2>After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.
Therefore,
Where:
<em>E</em> is the total energy
<em>PE</em> is the potential energy
<em>KE</em> is the kinetic energy
<em>m</em> is the mass of the object
<em>g</em> is the gravitational acceleration
<em>h </em>is the reached height of the object
<em>v</em> is the velocity of the object
Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:
Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.
So,
Hence,
The height at the second moment (maximum height) is 8.62m
Have a nice day!