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Vladimir [108]
3 years ago
9

How much force is required to hold an empty carton of volume 1.5 L beneath the surface in a sink of water? Assume the carton is

empty, so its own weight is negligibly small.
Physics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

It will require 14.715 N of force to hold the cartoon beneath the water.

Explanation:

Given the the volume of cartoon is 1.5 liters.

We need to find the force required to hold this cartoon beneath the water.

As we know from the Archimedes principle that the net force is equal to the volume of liquid displaced.

Given volume of the cartoon is 1.5 liters. So, 1.5 liters of water will be displaced.

And we know the density of the water is 1000\ kg/m^3. That is 1\ kg/L

And g=9.81\ m/s^2

F_N=\rho Vg\\F_N=1\times 1.5\times 9.81\\F_N=14.715\ N

So, it will require 14.715 N of force to hold 1.5 liter volume of cartoon beneath the water.

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8. At what position does the mass have the greatest acceleration?
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Option (e)

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If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.

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a ball rolls along the floor with a constant velocity of 3 m/s. How far will it have gone after 234 seconds?
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Problem 4: A uniform flat disk of radius R and mass 2M is pivoted at point P A point mass of 1/2 M is attached to the edge of th
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From the case we know that:

  1. The moment of inertia Icm of the uniform flat disk witout the point mass is Icm = MR².
  2. The moment of inerta with respect to point P on the disk without the point mass is Ip = 3MR².
  3. The total moment of inertia (of the disk with the point mass with respect to point P) is I total = 5MR².

Please refer to the image below.

We know from the case, that:

m = 2M

r = R

m2 = 1/2M

distance between the center of mass to point P = p = R

Distance of the point mass to point P = d = 2R

We know that the moment of inertia for an uniform flat disk is 1/2mr². Then the moment of inertia for the uniform flat disk is:

Icm = 1/2mr²

Icm = 1/2(2M)(R²)

Icm = MR² ... (i)

Next, we will find the moment of inertia of the disk with respect to point P. We know that point P is positioned at the arc of the disk. Hence:

Ip = Icm + mp²

Ip = MR² + (2M)R²

Ip = 3MR² ... (ii)

Then, the total moment of inertia of the disk with the point mass is:

I total = Ip + I mass

I total = 3MR² + (1/2M)(2R)²

I total = 3MR² + 2MR²

I total = 5MR² ... (iii)

Learn more about Uniform Flat Disk here: brainly.com/question/14595971

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