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Vladimir [108]
2 years ago
9

How much force is required to hold an empty carton of volume 1.5 L beneath the surface in a sink of water? Assume the carton is

empty, so its own weight is negligibly small.
Physics
1 answer:
Gwar [14]2 years ago
6 0

Answer:

It will require 14.715 N of force to hold the cartoon beneath the water.

Explanation:

Given the the volume of cartoon is 1.5 liters.

We need to find the force required to hold this cartoon beneath the water.

As we know from the Archimedes principle that the net force is equal to the volume of liquid displaced.

Given volume of the cartoon is 1.5 liters. So, 1.5 liters of water will be displaced.

And we know the density of the water is 1000\ kg/m^3. That is 1\ kg/L

And g=9.81\ m/s^2

F_N=\rho Vg\\F_N=1\times 1.5\times 9.81\\F_N=14.715\ N

So, it will require 14.715 N of force to hold 1.5 liter volume of cartoon beneath the water.

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Surviving a ship wreck, what is the minimum mass of wood (density 60% that of sea water) necessary to support a 70kg woman stand
Shkiper50 [21]

To solve this problem we will apply the concepts related to the principle of archimedes. for which we will summarize that the bearing force must be equivalent to the mass of the individual and the mass of the way. Said mass of wood will be expressed in terms of density and volume. Finally with the values found we will proceed to find the Volume of the wood and thus find the mass.

(M_{woman}+M_{wood})g=F_B

(M_{woman}+M_{wood})g=V\rho_{water} g

(M_{woman}+V \rho_{wood})g=V\rho_{water} g

(M_{woman}+V \rho_{wood})=V\rho_{water}

For the relation between density and Volume we have that,

mass=density\times volume

Where given that,

Mass of woman, M_{man}=70kg

If the density of the wood is 60% the density of the water we will have to

Density of water, \rho_{water}=1000kg/m^{3}

And density of wood is

\rho_{wood}=600kg/m^{3}

Now the mass of the man can be expressed as

M_{woman}=V\rho_{water} -V\rho_{wood}

V=\frac{M_{woman}}{\rho_{water} -\rho_{wood}}=\frac{70\;kg}{1000\;kg/m^{3}-600\;kg/m^{3}}

V=0.175m^{3}

Mass of wood required is given by,

M_{wood}=V\rho_{wood}=0.175m^{3}\times600kg/m^{3}

\mathbf{\therefore M_{wood}=105kg}

Therefore the minimum mass necessary to support a 70kg Woman is 105Kg.

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The above explains why the classical assumptions lead to a wrong spectrum.

Explanation:

i don't know if It helps you..parang Ang layo naman Ng sagot ko sa tanong mo

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