Melting gold bars is the process that involves an increase in entropy
Answer:
yes is it yes yes yes yes yes yes yes yes yes yes
According to TABC laws on alcohol use, it is illegal to sell alcohol in many places in texas thus no you can't discount alcohol in Texas.
Alcohol is prohibited in many parts of Texas thus anyone under the age of 21 may not be sold alcohol, including adults. Beer and wine may be purchased from licensed establishments Monday through Friday from 7:00 a.m. to midnight. On Saturday, they may sell them from 7:00 a.m. until 1:00 p.m. Additionally, they may sell on Sundays from noon to midnight. Only liquor stores, nevertheless, are allowed to sell distilled alcohol. On Sundays before noon, restaurants are allowed to serve alcoholic beverages with food. On the other hand, it is prohibited to sell any alcoholic beverages with a volume of more than 17% on Sunday (ABV). On Thanksgiving Day, New Year's Day, or Christmas Day, no establishment may offer any alcoholic beverages. Alcohol from a single producer cannot be sold by a restaurant or other retailer. And alcohol cannot be sold by food trucks.
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Answer:
Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.
Explanation:
- It is a stichiometry problem.
- We should write the balance equation of the mentioned chemical reaction:
<em>2Al + 3CuCl₂ → 3Cu + 2AlCl₃.</em>
- It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.
- Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:
<em>n = mass / molar mass</em>
- The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.
- The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³ mol.
- <em>From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.</em>
∴ 3.85 x 10⁻³ mol of Al foil reacts completely with 5.578 x 10⁻³ mol of CuCl₂ with <em>(2:3)</em> ratio and CuCl₂ is the limiting reactant while Al foil is in excess.
- From the stichiometry 3.0 moles of CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).
- So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.
- Finally, we can calculate the mass of copper produced using:
mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³ mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.
- <u><em>So, the answer is:</em></u>
<em>Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.</em>
Answer:
I am confused as to what you're asking.
