Answer:
K₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2KOH(aq)
Explanation:
The type of reaction is Double Displacement (Metathesis)
Answer: Option (D) is the correct answer.
Explanation:
A polymer is a large molecule which contains repeating units.
A polymer forms long chain of atoms which are not necessarily arranged in a ring structure. There are not only double bonds between all the carbon atoms, as there can be single bonds or triple bonds between the atoms of a polymer.
A polymer does not contain many different type of molecules as there are many repeating units and not many molecules in a polymer.
A polymer is made of large molecules with repeating units.
Thus, we can conclude that option (D) is the correct answer.
We are going to use this formula:
E° = 0.0592/ n * ㏒K
when E° is the standard state cell potential
and n is number of moles of electrons transferred in the balanced equation
for the reaction of the cell.
Sr(s) + Mg2+ (aq) ↔ Sr2+(aq) + Mg(s)
we can get it by using the given balanced equation, we here have 2 electrons
transferred so, n = 2
and K the equilibrium constant = 3.69 x 10^17
so, by substitution:
∴ E° = 0.0592 / 2 * ㏒ (3.69 x 10^17)
= 0.52 V
Answer:
ΔG = - 590.20 kJ/mol
Explanation:
The formula for calculating Gibb's Free Energy can be written as:
ΔG = ΔH - TΔS
Given That:
ΔH = -720.5 kJ/mol
T = 221.0°C = (221.0 + 273.15) = 494.15 K
ΔS° = -263.7 J/K
So; ΔS° = -0.2637 kJ/K if being converted from joule to Kilo-joule
Since we are all set, let replace our given data in the above equation:
ΔG = (-720.5 kJ/mol) - (494.15 K) ( - 0.2637 kJ/K)
ΔG = (-720.5 kJ/mol) - (- 130.30755)
ΔG = -720.5 kJ/mol + 130.30755
ΔG = -590.192645 kJ/mol
ΔG = - 590.20 kJ/mol
Thus, The value of ΔG° at 221.0°C for the formation of phosphorous trichloride from its constituent elements, P2(g) + 3Cl2(g) → 2PCl3(g) is <u>-590.20</u> kJ/mol.
