Answer:
b, d, e
Explanation:
Three type basic static stresses to which a material can be subjected are
Tensile: Stress generated due to elongation force on the body.
Compressive: The stress generated when the body is compressed.
Shear: The stress generated when a force parallel to cross-section are of the body.
Hardness, reduction in area and true stress are material properties.
Answer:
62.73g
Explanation:
Using the following formula;
Molarity = n/V
Where;
n = number of moles (mol)
V = volume (L)
From the information given below,
V = 230mL = 230/1000 = 0.230L
M = 3.21 M
3.21 = n/0.230
n = 3.21 × 0.230
n = 0.738 mol of KNO2
Molar mass of KNO2 = 39 + 14 + 16(2)
= 53 + 32
= 85g/mol
mole = mass/molar mass
0.738 mol = mass/85g/mol
Mass = 0.738 × 85
mass = 62.73g
Answer:
It is better to use direct quotation rather than summarizing or paraphrasing when you want to share the author's original words.
Explanation:
In writing, it is sometimes necessary to share an authors original words in order to buttress a point or validate an argument. In such cases where it is necessary to use exactly the same diction as the author in order to communicate a point clearly, it is apt to use a direct quotation rather than attempting to summarize or paraphrase the original words of the author.
Hence direct quotation is used to share an author's original words.
Given :
The student looks up the value of the appendix of his textbook but cannot find a value for NaCl.
To Find :
Why the Ksp of NaCl is not present .
Solution :
Ksp values are given for those compounds which are partially soluble or insoluble in water .
But , we know NaCl is strong electrolyte and it completely dissociated in water .
So , the reaction go forward and their is no need to calculate Ksp .
Therefore , the Ksp of NaCl is not present .
Hence , this is the required solution .
Answer:
We need 69 grams of NaHCO3
Explanation:
Step 1: Data given
Volume = 550 mL = 0.550 L
Molarity H2SO4 = 0.75 M
Step 2: The balanced equation
H2SO4(aq) + 2NaHCO3(aq) → Na2SO4(aq) + 2H2O(l) + 2CO2(g)
Step 3: Calculate moles of H2SO4
Moles H2SO4 = molarity * volume
Moles H2SO4 = 0.75 M * 0.550 L
Moles H2SO4 = 0.4125 moles H2SO4
Step 4: Calculate moles NaHCO3
For 1 mol H2SO4 we need 2 moles NaHCO3 to produce 1 mol Na2SO4 and 2 moles H2O and 2 Moles CO2
For 0.4125 moles H2SO4 we need 2*0.4125 = 0.825 moles NaHCO3
Step 5: Calculate mass NaHCO3
Mass NaHCO3 = moles * molar mass
Mass NaHCO3 = 0.825 moles * 84.0 g/mol
Mass NaHCO3 = 69.3 grams ≈ 69 grams
We need 69 grams of NaHCO3