Answer:
We need 69 grams of NaHCO3
Explanation:
Step 1: Data given
Volume = 550 mL = 0.550 L
Molarity H2SO4 = 0.75 M
Step 2: The balanced equation
H2SO4(aq) + 2NaHCO3(aq) → Na2SO4(aq) + 2H2O(l) + 2CO2(g)
Step 3: Calculate moles of H2SO4
Moles H2SO4 = molarity * volume
Moles H2SO4 = 0.75 M * 0.550 L
Moles H2SO4 = 0.4125 moles H2SO4
Step 4: Calculate moles NaHCO3
For 1 mol H2SO4 we need 2 moles NaHCO3 to produce 1 mol Na2SO4 and 2 moles H2O and 2 Moles CO2
For 0.4125 moles H2SO4 we need 2*0.4125 = 0.825 moles NaHCO3
Step 5: Calculate mass NaHCO3
Mass NaHCO3 = moles * molar mass
Mass NaHCO3 = 0.825 moles * 84.0 g/mol
Mass NaHCO3 = 69.3 grams ≈ 69 grams
We need 69 grams of NaHCO3
