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kifflom [539]
2 years ago
11

A scientist was in the field when he saw a mineral sample. He wanted to determine the relative hardness of the mineral, so he co

nducted scratch tests. He summarized his results in a table. A 2 column table with 4 rows. The first column is labeled Mineral with known hardness with entries: Chalcopyrite, pyrite, Orthoclase, Quartz. Second column is labeled Was a scratch produced? with entries: Yes, Yes, Yes, No. What conclusion can you make about the hardness of the mineral?.
Chemistry
1 answer:
Crazy boy [7]2 years ago
3 0

The mineral hardness depends on its resistance to being scratched. Mohs scale is used to determine the hardness of an unknown mineral.<em> The unknown mineral is harder than Orthoclase, but not harder than Quartz</em>.

-------------------------

The hardness of a mineral is its resistance to being scratched or marked on the surface by another material.

Several elements are used to test the hardness of a mineral, like another mineral of known hardness.

Many different scales can be used to identify the mineral. However, the most commonly used is the Mohs scale.

Let us say that you have two minerals. You already know which mineral is one of them and its hardness.

  • If the unknown mineral scratches the known mineral, means that the first one is harder than the second one.

  • But if the unknown mineral does not get to scratch the known one, it means they are equally hard, or the known mineral is harder than the unknown one.

In the exposed example, the table must be as follows

<u>     Mineral                     Was a scratch produced?               </u>

Chalcopyrite                               YES

pyrite                                           YES

Orthoclase                                  YES                                          

<u>Quartz                                          NO                                            </u>

Quartz is the hardest of these minerals. Its hardness level is 7 according to the Mohs scale.

Because scratches were produced using <em>Chalcopyrite, Pyrite, and Orthoclase</em>, we can assume that the unknown mineral is harder than these three ones.

However, no scratch was produced using quartz, suggesting that the unknown mineral is<em> between orthoclase and quartz </em>in the Mohs scale.

<em>The </em><em>unknown mineral</em><em> is </em><em>harder</em><em> than </em><em>Orthoclase</em><em>, but </em><em>not harder</em><em> than </em><em>Quartz</em><em>. It is between </em><em>6 </em><em>and </em><em>7 </em><em>hardness levels.</em>

---------------------------

You can learn more about the Mohs scale at

brainly.com/question/198363

brainly.com/question/1585664

brainly.com/question/10202262

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In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
For the diprotic weak acid h2a, ka1 = 3.2 × 10-6 and ka2 = 6.1 × 10-9. what is the ph of a 0.0650 m solution of h2a? what are th
Stolb23 [73]
Given:

Diprotic weak acid H2A:
 
Ka1 = 3.2 x 10^-6
Ka2 = 6.1 x 10^-9. 
Concentration = 0.0650 m 

Balanced chemical equation:

H2A ===> 2H+  + A2- 
0.0650       0        0
-x                2x       x
------------------------------
0.065 - x     2x      x

ka1 = 3.2 x 10^-6 = [2x]^2 * [x] / (0.065 - x)

solve for x and determine the concentration at equilibrium. 


5 0
2 years ago
A sample of helium gas initially at 37.0°C, 785 torr and 2.00 L was heated to 58.0°C while the volume expanded to 3.24 L. What i
spayn [35]

Answer:

0.681 atm

Explanation:

To solve this problem, we make use of the General gas equation.

Given:

P1 = 785 torr

V1 = 2L

T1 = 37= 37 + 273.15 = 310.15K

P2 = ?

V2 = 3.24L

T2 = 58 = 58+273.15 = 331.15K

P1V1/T1 = P2V2/T2

Now, making P2 the subject of the formula,

P2 = P1V1T2/T1V2

P2 = [785 * 2 * 331.15]/[310.15 * 3.24]

P2 = 515.715 Torr

We convert this to atm: 1 torr = 0.00132 atm

515.715 Torr = 515.715 * 0.00132 = 0.681 atm

8 0
3 years ago
&lt;
victus00 [196]

Answer:

This isotope has 59 electrons giving it a charge of -2.

Explanation:

To find this we have to understand isotope relates to the mass of the nucleus. This isotope has 59 electrons to counter the protons and give it a negative charge.

6 0
2 years ago
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scoray [572]

Answer:

I believe it's A

Explanation:

Hope this helps! ^-^

8 0
3 years ago
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