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kirill115 [55]
3 years ago
10

Which property would cesium most likely have?

Chemistry
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0
The answer is a because its not low ductile or gasst

ivolga24 [154]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

Cesium is a group 1A element and therefore, it is a metal. Alkali metals are soft, malleable and ductile.

And, group 1A elements being metals are good conductors of heat and electricity.

Group 1A elements are highly reactive in nature. Hence, cesium is also reactive in nature.  Also, cesium is not a gas.

Therefore, we can conclude that a property cesium would most likely have is that it is ductile.

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Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. C2H6 + O2 → CO2 + H2O
fenix001 [56]
Step 1: Write the unbalanced equation,

                                 C₂H₆  +  O₂    →    CO₂  +  H₂<span>O

There are 2 C at left hand side and 1 carbon at right hand side. So, multiply CO</span>₂ by 2 to balance C atoms at both side. So,

                                 C₂H₆  +  O₂    →   2 CO₂  +  H₂O

Now, count number of H atoms at both sides. There are 6 H atoms at left hand side and 2 at right hand side. Multiply H₂O by 3 to balance H atoms.


                                 C₂H₆  +  O₂    →   2 CO₂  +  3 H₂O

At last, balance O atoms. There are 2 O atoms at left hand side and 3 O atoms at right hand side. Multiply O₂ with 1.5 (i.e. 3/2) to balance O atoms. i.e.

                                 C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O

Hence, the equation is balanced. If you want to make equation fraction free then multiply all equation with 2. i.e.

                           ( C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O ) × 2

                                2 C₂H₆  +  3 O₂    →   4 CO₂  +  6 H₂O
5 0
3 years ago
Read 2 more answers
Encountering problems during separation/purification is a very common issue in organic synthesis, but these steps are crucial to
Rus_ich [418]
True is the correct answer! your welcome! :)
8 0
3 years ago
Write a balanced nuclear equation for the formation of 28 Si 14 from beta-minus emission.
Fantom [35]

Answer:

Phosphorus-28 undergoes beta-minus decay to produce

  • an electron,
  • a Silicon-28 nuclei, and
  • an electron antineutrino.

\rm ^{28}_{13} Al \to ^{28}_{14} Si + ^{\phantom{-}0}_{-1}e + \bar{\mathnormal{v}}_{\rm e}

Explanation:

In simple words, when a nucleus undergoes beta-minus decay, a neutron is converted to a proton. An electron and an electron antineutrino will be released.

\rm ^{1}_{0}n^{0} \to ^{1}_{1}p^{+} + ^{\phantom{-}0}_{-1}e^{-} + \bar{\mathnormal{v}}_{\rm e}.

One way to tell whether a neutron is converted to a proton, but not vice versa, is to check the sum charges on the two sides of this equation.

  • Left-hand side: 0. Neutron is neutral.
  • Right-hand side: 1 + (-1) = 0. Each proton carries a charge of +1. Each electron (beta-minus particle) carries a charge of -1. Antineutrinos are neutral.

The charges on the two sides of this equation is the same. Hence this nuclear equation is possible (but not necessarily correct; however, if the proton and the neutron are in the wrong place the charge won't even be the same.)

Since the mass number of a proton and a neutron are both 1, the overall mass number of the atom will stay the same.

The atomic number is the number of protons in each atom. That number determines the symbol and the chemical properties of the atom. When one neutron in an atom is converted to a proton, the atomic number of the atom will increase by 1.

The atomic number of the daughter nucleus, silicon, is 14. It takes a parent nucleus with atomic number 14 - 1 = 13 to produce a silicon atom. Refer to a modern periodic table. Atomic number 13 corresponds to the element aluminum.

Also, the mass number of the daughter nucleus is 28. Since the mass number would stay the same in a beta decay, the mass number of the parent nucleus would also be 28. In other words, it takes an aluminum-28 atom to undergo beta-decay to produce a silicon-28 atom.

Complete the other details (electron and electron antineutrino) to obtain the equation

\rm ^{28}_{13} Al \to ^{28}_{14} Si + ^{\phantom{-}0}_{-1}e + \bar{\mathnormal{v}}_{\rm e}.

6 0
3 years ago
The units of work are force and energy im not sure if im right
Andrej [43]
The unit for work is ENERGY
6 0
3 years ago
Read 2 more answers
What is the value of quantum numbers (n, l, ml, ms) of 2p^3?​
eduard

Answer:

Explanation:

First digit of the 2p^3  gives you value of n,  in this case its = 2, So, n= 2

Second alphabet gives you the value of l,

l=0 =s

l=1 =p

l=3=d

l=4=f

since  "p" is the alphabet  in 2p^3, so in your case lt shoudlbe = 1 right?

ml= -l to +l , that is -1, 0, +1

Ms= +1/2  or -1/2 alaways remains same foe evrything.

6 0
3 years ago
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