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ololo11 [35]
3 years ago
5

An electron is accelerated from rest through a potential difference of 300V. it then passes through a uniform 0.001-T magnetic f

ield, oriented perpendicular to the electrons velocity. what is the magnitude of the magnetic force on the electron?
Physics
1 answer:
meriva3 years ago
3 0

Given :

Potential difference, V = 300 V.

Magnetic Field, B = 0.001 T.

To Find :

The magnitude of the magnetic force on the electron.

Solution :

We know, for perpendicular orientation, force is given by :

F = qVB\\\\F = 1.6 \times 10^{-19} \times 300\times 0.001\ N\\\\F = 4.8\times 10^{-20}\ N

Hence, this is the required solution.

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A speed truck locks it’s brakes and it skids to a stop. If the truck’s total mass were doubled, it’s skidding distance would be?
Gnom [1K]

Answer:

The skidding distance would be doubled

Explanation:

When the truck applies the brakes and slows down, its motion is a uniformly accelerated motion, so its skidding distance can be found by using the suvat equation

v^2-u^2=2as

where

v = 0 is the final velocity (zero since the truck comes to a stop)

u is the initial velocity

a is the acceleration

s is the skidding distance

The acceleration can also be written as

a=\frac{F}{m}

where F is the force applied by the brakes and m the mass of the truck. Substituting into the previous equation,

-u^2 = 2\frac{F}{m}s\\s = -\frac{mu^2}{2F}

We see that the skidding distance is proportional to the mass: therefore, if the mass of the truck is doubled, the skidding distance will double as well.

5 0
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Help me please!<br> What is the velocity of a 0.1 kg baseball whose momentum is 100?
Nikitich [7]

Answer:

1000m/s

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velocity(v)=momentum(p)/mass

=100/.1

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3 0
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Atoms with the same number of protons but different numbers of neutrons are called isomers
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8 0
3 years ago
A 85.0kg man and a 65, 0kg woman are riding a Ferris wheel with a radius of 20.0m. What is the Ferris wheels tangential velocity
zvonat [6]

Answer:

The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is <u>3.92 m/s</u>.

Explanation:

Let's use <u>Newton's 2nd Law</u> to help solve this problem.

  • F = ma

The force acting on the Ferris wheel is the centripetal force, given in the problem: F_c=115 \ \text{N}.

The mass "m" is the <u>sum</u> of the man and woman's masses: 85+65= 150 \ \text{kg}.

The acceleration is the centripetal acceleration of the Ferris wheel: a_c=\displaystyle \frac{v^2}{r}.

Let's write an equation and solve for "v", the tangential (linear) acceleration.

  • \displaystyle 115=m(\frac{v^2}{r} )
  • \displaystyle 115 = (85+65)(\frac{v^2}{20})
  • \displaystyle 115=150(\frac{v^2}{20} )
  • .766667=\displaystyle(\frac{v^2}{20} )
  • 15.\overline{3}=v^2
  • v=3.9158

The Ferris wheel's tangential velocity is 3.92 m/s.

8 0
2 years ago
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