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Sindrei [870]
2 years ago
6

Enumerate the function of each parts of alimentary canal in order from ingestion to egestion ​. ?

Physics
1 answer:
SOVA2 [1]2 years ago
3 0

Answer:

Human digestive system involves gastrointestinal tract and other components such as liver, intestines, glands, mouth, stomach, gallbladder. The Human Digestive System Process has six primary tasks: ingestion, motility, secretion, digestion, absorption, excretion.

Explanation:

Hope it helps

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Two equal forces are applied to a door. The first force is applied at the midpoint of the door; the second force is applied at t
TEA [102]

Answer: The second force applied to the doorknob

Explanation:

The formulae for torque is simple the product of the applied force and the perpendicular distance.

The greater the perpendicular force, the greater the torque assuming a constant value of force.

Applying the force at the doorknob gives for a greater distance between the force and the turning point compared to applying the force at the midpoint of the door ( which is at a shorter distance)

6 0
3 years ago
What type of heat transfer is happening when the sun warms your face
Talja [164]
Answer:it might be radiation


Explanation:
7 0
3 years ago
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Могут ли быть сообщающиеся сосуды неодинаковы пр своей форме
Rudik [331]

Answer:

no

Explanation:

they cannot because they contain the same amount of liquid

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3 years ago
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Initial velocity 10 m/s accelerates at 5 m/s for 2 seconds whats the final velocity
stiks02 [169]

Answer:

<em>The final velocity is 20 m/s.</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

v_f=v_o+at

The provided data is: vo=10 m/s, a=5\ m/s^2, t=2 s. The final velocity is:

v_f=10~m/s+5\ m/s^2\cdot 2\ s

v_f=20\ m/s

The final velocity is 20 m/s.

8 0
3 years ago
A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above t
ycow [4]

Answer:

Explanation:

Applied force, F = 18 N

Coefficient of static friction, μs = 0.4

Coefficient of kinetic friction, μs = 0.3

θ = 27°

Let N be the normal reaction of the wall acting on the block and m be the mass of block.

Resolve the components of force F.

As the block is in the horizontal equilibrium, so

F Cos 27° = N

N = 18 Cos 27° = 16.04 N

As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .

The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N   .... (1)

The vertically downward force acting on the block is mg - F Sin 27°

                                                      = mg - 18 Sin 27° = mg - 8.172    ... (2)

Now by equating the forces from equation (1) and (2), we get

mg - 8.172 = 6.42

mg = 14.592

m x 9.8 = 14.592

m = 1.49 kg

Thus, the mass of block is 1.5 kg.  

6 0
3 years ago
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